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ddd [48]
3 years ago
6

2.How could you identify an element by its number of protons?

Chemistry
2 answers:
kipiarov [429]3 years ago
8 0

Answer:

The number of protons determines an element's atomic number (Z) and distinguishes one element from another. For example, carbon's atomic number (Z) is 6 because it has 6 protons. The number of neutrons can vary to produce isotopes, which are atoms of the same element that have different numbers of neutrons.

marysya [2.9K]3 years ago
6 0
The number of protons determines an elements atomic number and distinguishes one element from another. For example, carbons atomic number is six because it has six protons. The number of neutrons can vary to produce isotopes, which are atoms of the same element that have different numbers of neutrons
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The Grand Canyon becomes deeper every day. What causes the canyon to<br> become deeper?
choli [55]

Answer:

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8 0
4 years ago
Read 2 more answers
which of the following is a balanced chemical equation for the reaction of magnesium with nitrogen gas to form magnesium nitride
ioda
So the unbalanced equation would be Mg + N^2 --> Mg^3N^2

Which means the balanced equation would be 3Mg + N^2 --> Mg^3N^2

This is balance the equation out since you now has 3 magnesium and 2 nitrogen on the left side, and 3 magnesium on 2 nitrogen on the right. Double check my work though, it's been awhile.
8 0
4 years ago
What characteristics does the serval have that make it well-suited to life on the savanna ?
nika2105 [10]
It is very camouflaged this way it will survive longer then most other animals

5 0
3 years ago
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How many grams (g) are in 0.250 moles of copper?
MissTica

Answer:

15.89grams

Explanation:

The mass of a substance can be calculated from it's mole value by using the formula:

mole = mass/molar mass

According to this question, there are 0.250 moles of copper. Hence, the mass of copper can be calculated as follows:

Molar mass of Cu = 63.55g/mol

0.250 = mass/63.55

mass = 0.250 × 63.55

mass = 15.8875

Mass of Cu in 0.250mol is 15.89grams.

5 0
3 years ago
Neptunium-237 undergoes a series of α-particle and β-particle productions to end up as thallium-205. How many α particles and β
Fantom [35]
<h3>Answer:</h3>

8 alpha particles

4 beta particles

<h3>Explanation:</h3>

<u>We are given;</u>

  • Neptunium-237
  • Thallium-205
  • Neptunium-237 undergoes beta and alpha decay to form Thallium-205.

We are required to determine the number of beta and alpha particles produced to complete the decay series.

  • We need to know that when a radioisotope emits an alpha particle the mass number reduces by 4 while the atomic number decreases by 2.
  • When a beta particle is emitted the mass number of the radioisotope increases by 1 while the atomic number remains the same.

In this case;

Neptunium-237 has an atomic number 93, while,

Thallium-205 has an atomic number 81.

Therefore;

²³⁷₉₃Np → x⁴₂He + y⁰₋₁e + ²⁰⁵₈₁Ti

We can get x and y

237 = 4x + y(0) + 205

237-205 = 4x

4x = 32

 x = 8

On the other hand;

93 = 2x + (-y) + 81

but x = 8

93 = 16 -y + 81

y = 4

Therefore, the complete decay equation is;

²³⁷₉₃Np → 8⁴₂He + 4⁰₋₁e + ²⁰⁵₈₁Ti

Thus, Neptunium-237 emits 8 alpha particles and 4 beta particles to become Thallium-205.

5 0
3 years ago
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