Answer:
See explanation
Explanation:
The oxides or hydrides are formed by exchange of valency between the two atoms involved. The group of the atom bonded to oxygen or hydrogen in the binary compound can be deduced by considering the subscript attached to the oxygen or hydrogen atom.
Now let us take the journey;
R2O3- refers to an oxide of a group 13 element, eg Al2O3
R2O - refers to an oxide of group a group 1 element e.gNa2O
RO2 - refers to an oxide of a group 14, 15 or 16 element such as CO2, NO2 or SO2
RH2 - refers to the hydride of a group 12 element Eg CaH2
R2O7 - refers to an oxide of a group 17 element E.g Cl2O7
RH3- refers to a hydride of a group 13 element E.g AlH3
Answer:
I' really don't know I'm sorry
Answer:
0.99mol/L
Explanation:
Molarity ( M) = # of moles of solute / volume of solution (L)
Volume of Solution = 100 mL or 0.1 L
Molarity ( M) = # of moles of solute / volume of solution (L)
Molarity (M) = 0.099 mol / 0.1 L = 0.99mol/ L
A heterogeneous mixture cannot be considered a single phase
Answer: The number of moles of excess reagent remain unreacted will be, 6.004 moles.
Explanation : Given,
Moles of 
= 1.332 mol
Mass of 
= 6.504 mol
First we have to calculate the limiting and excess reagent.
The balanced chemical equation is:
From the balanced reaction we conclude that
As, 13 mole of react with 1 mole of
So, 6.504 moles of react with 
moles of
From this we conclude that, is an excess reagent because the given moles are greater than the required moles and is a limiting reagent and it limits the formation of product.
Number of moles remain unreacted = 6.504 mol - 0.5003 mol = 6.004 mol
Therefore, the number of moles of excess reagent remain unreacted will be, 6.004 moles.
