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Kazeer [188]
3 years ago
5

When cations and anions join, they form what

Chemistry
1 answer:
uranmaximum [27]3 years ago
6 0

Answer:

ionic

Explanation:

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Identify the group number of following oxides/hydrides in Mendeleev
Ivan

Answer:

See explanation

Explanation:

The oxides or hydrides are formed by exchange of valency between the two atoms involved. The group of the atom bonded to oxygen or hydrogen in the binary compound can be deduced by considering the subscript attached to the oxygen or hydrogen atom.

Now let us take the journey;

R2O3- refers to an oxide of a group 13 element, eg Al2O3

R2O - refers to an oxide of group a group 1 element e.gNa2O

RO2 - refers to an oxide of a group 14, 15 or 16 element such as CO2, NO2 or SO2

RH2 - refers to the hydride of a group 12 element Eg CaH2

R2O7 - refers to an oxide of a group 17 element E.g Cl2O7

RH3- refers to a hydride of a group 13 element E.g AlH3

5 0
3 years ago
Please help this is due today which ones are reactive and which arent?​
BARSIC [14]

Answer:

I' really don't know I'm sorry

4 0
3 years ago
A 100. mL volume of 0.800 M calcium chloride is mixed with 400. mL of water to make 500. mL of solution. What is the final molar
strojnjashka [21]

Answer:

0.99mol/L

Explanation:

Molarity ( M) = # of moles of solute / volume of solution (L)

Volume of Solution = 100 mL or 0.1 L

Molarity ( M) = # of moles of solute / volume of solution (L)

Molarity (M) = 0.099 mol / 0.1 L = 0.99mol/ L

3 0
4 years ago
Which of the following cannotbe considered a single phase? a heterogeneous mixture a pure solid a homogeneous mixture a pure liq
MrRa [10]
A heterogeneous mixture cannot be considered a single phase
4 0
3 years ago
If 1.332 mol of C4H10 are reacted with 6.504 mol of O2, how many mol of the excess reagent will remain unreacted? 2 C4H10 + 13 O
Luden [163]

Answer: The number of moles of excess reagent remain unreacted will be, 6.004 moles.

Explanation : Given,

Moles of C_4H_{10} = 1.332 mol

Mass of O_2 = 6.504 mol

First we have to calculate the limiting and excess reagent.

The balanced chemical equation is:  

C_4H_{10}+13O_2\rightarrow 10H_2O+8CO_2

From the balanced reaction we conclude that

As, 13 mole of O_2 react with 1 mole of C_4H_{10}

So, 6.504  moles of O_2 react with \frac{6.504}{13}=0.5003 moles of C_4H_{10}

From this we conclude that, C_4H_{10} is an excess reagent because the given moles are greater than the required moles and O_2 is a limiting reagent and it limits the formation of product.

Number of moles remain unreacted = 6.504 mol - 0.5003 mol = 6.004 mol

Therefore, the number of moles of excess reagent remain unreacted will be, 6.004 moles.

5 0
4 years ago
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