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lesantik [10]
2 years ago
12

1.) If z = 3, which statement is true about the equation 7(2+5x)=3x+14?

Mathematics
1 answer:
olasank [31]2 years ago
4 0

Answer:

answer is D I hope u get it

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Use properties to find the sum or product<br>8 x 51
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8(51)

=8(50+1)

=8*50+8*1

=8*5*10+8*1

=400+8

=408

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Can someone help me? I pick brainlest
bulgar [2K]

Answer:

?=8

Step-by-step explanation:

52/ 13 = 4

32/4= ? = 8

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Using trig how do you answer this
Aneli [31]

Answer:

62.73° or 1.09 radians

Step-by-step explanation:

SOH CAH TOA

sin = \frac{opposite}{hypotenuse}, so sin (?) = \frac{8}{9}

this means that ? = sin^{-1}(\frac{8}{9}) or ? = arcsin(\frac{8}{9}), depending on what calculator you have

plugging in sin^{-1}(\frac{8}{9}) or arcsin(\frac{8}{9}) into calculator will get you

62.73° or 1.09 radians

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3 years ago
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Solve the equation.<br><br> t-12=3
Elis [28]

<em>Answer:</em>

<em>t = 15</em>

<em>Step-by-step explanation:</em>

<em>t - 12 = 3</em>

<em>t = 3 + 12</em>

<em>t = 15</em>

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A statistics student wants to compare his final exam score to his friend's final exam score from last year; however, the two exa
yarga [219]

Answer:

z= \frac{85-70}{10}=1.5

z= \frac{45-35}{5}=2

So then the correct answer for this case is:

B) Our student, Z= 1.50; his friend, Z=2.00.

Step-by-step explanation:

Assuming this complete question:

A statistics student wants to compare his final exam score to his friend's final exam score from last year; however, the two exams were scored on different scales. Remembering what he learned about the advantages of Z scores, he asks his friend for the mean and standard deviation of her class on the exam, as well as her final exam score. Here is the information:

Our student: Final exam score = 85; Class: M = 70; SD = 10.

His friend: Final exam score = 45; Class: M = 35; SD = 5.

The Z score for the student and his friend are:

A) Our student, Z= -1.07; his friend, Z= -1.14.

B) Our student, Z= 1.50; his friend, Z=2.00.

C) Our student, Z= 1.07; his friend, Z= -1.14.

D) Our student, Z= 1.07; his friend, Z= 1.50

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution

Let X the random variable that represent the scores for our student, and for this case we know that:

E(X)= \mu =70, SD_X=\sigma=10  

The z score is given by:

z=\frac{x-\mu}{\sigma}

If we use this we got:

z= \frac{85-70}{10}=1.5

Let Y the random variable that represent the scores for his friend, and for this case we know that:

E(Y)= \mu =35, SD_Y=\sigma=5  

The z score is given by:

z=\frac{y-\mu}{\sigma}

If we use this we got:

z= \frac{45-35}{5}=2

So then the correct answer for this case is:

B) Our student, Z= 1.50; his friend, Z=2.00.

3 0
3 years ago
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