Answer:
4.15 x 10^6 N
Explanation:
Area, A = 1.43 cm^2 = 1.43 x 10^-4 m^2
mass, m = 60.5 kg
Weight, F = m g = 60.5 x 9.8 = 592.9 N
Pressure = Force / Area
P = Weight / Area
P = 592.9 / (1.43 x 10^-4)
P = 4.15 x 10^6 N
Answer:
0.1 L
Explanation:
From the question given above, we obtained the following data:
Initial volume (V₁) = 0.05 L
Initial Pressure (P₁) = 207 KPa
Final pressure (P₂) = 101 KPa
Final volume (V₂) =?
We can obtain the new volume (i.e the final volume) of the gas by using the Boyle's law equation as illustrated below:
P₁V₁ = P₂V₂
207 × 0.05 = 101 × V₂
10.35 = 101 × V₂
Divide both side by 101
V₂ = 10.35 / 101
V₂ = 0.1 L
Thus, the new volume of the gas is 0.1 L
Initial volume of mercury is
V = 0.1 cm³
The temperature rise is 35 - 5 = 30 ⁰C = 30 ⁰K.
Because the coefficient of volume expansion is 1.8x10⁻⁴ 1/K, the change in volume of the mercury is
ΔV = (1.8x10⁻⁴ 1/K)*(30 ⁰K)(0.1 cm³) = 5.4x10⁻⁴ cm³
The cross sectional area of the tube is
A = 0.012 mm² = (0.012x10⁻² cm²).
Therefore the rise of mercury in the tube is
h = ΔV/A
= (5.4x10⁻⁴ cm³)/(0.012x10⁻² cm²)
= 4.5 cm
Answer: 4.5 cm
Answer:
Charge on each metal sphere will be 
Explanation:
We have given number of electron added to metal sphere A 
As both the spheres are connected by rod so half -half electron will be distributed on both the spheres.
So electron on both the spheres 
We know that charge on each electron 
So charge on both the spheres will be equal to 
So charge on each metal sphere will be equal to
Answer:
A. It must be zero
Explanation:
A spacecraft leaves the solar system at a velocity of 1,500 m/s. The net force on this spacecraft is zero. What can we say about the spacecraft's acceleration?
According to Newton's second law
Force = Mass × acceleration
If the net force is zero
0 = mass × acceleration
0 = ma
a = 0/m
a = 0m/s²
this shows that the acceleration will be zero If the net force is zero
