Answer:
option c
Explanation:
K.E=1/2mv(squared)
K.E=1/2x900x80x80
K.E=450x6400=2880000J
convert to KJ=2880000/1000=2880KJ
I’m guessing convection currents since you mention mantle and core, reminds me of heat
The centre of mass of the objects is (0,1)m .
What do you mean by Centre of mass?
The centre of mass is a position defined relative to an object or system of objects .
We have given
m1=2kg , y1= 3
m2= 3kg ,y2=2.5m
m3=2.5kg ,y3= 0m
m4=4kg , y4= -0.5m
Ycm=mixi/mi
→2×3+3×2.5+2.5×0+4×0.5/4.5
→1m
Centre of mass of these object is at (0,1)m .
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If the it took the object travelling at 25m/s 1 second to travel a quarter of the circle, it means a quarter of the circle is 25m (it travels 25m in one second).
If the quarter of the circle is 25m than the circumference of the circle is 100m.
We want to calculate the radius of the circle.
Remember that the equation for finding the circumference contains the radius. We can use that equation to solve for the radius.
Circumference = 2πr
π = pi or 3.1415...... ( a number )
r = radius
Since we know the circumference, plug it in.
100m = 2πr
solve for the radius by isolating r.
100m/2π = r
r = radius = 100m/2π = 50m/π = 50/π meters
<h2>
Answer: Radius = 50/π meters</h2>