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Dima020 [189]
3 years ago
10

The outer planets are similar to the planet Earth; they just happen to be farther away from the Sun.

Physics
2 answers:
Harrizon [31]3 years ago
5 0

Answer:

False

Explanation:

The inner planets are called terrestrial planets due to the surfaces are solid (similar to Earth)-made up of heavy metals, either have no moons or few moons.

The outer planets are called Jovian planets or gas giants because they are encased in gas.  They all have rings with plenty of moons.

san4es73 [151]3 years ago
3 0

Answer:

Explanation:

I belive it's TRUE

The outer planets are also called the Jovian planets or gas giants. Like the inner planets, the outer planets have similar characteristics to one another. The outer planets are so much larger than the inner planets that they make up 99 percent of the mass of the celestial bodies that orbit the Sun.

Here: https://www.universetoday.com/33292/the-outer-planets/

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True or false? Once the sun explodes, the whole solar system will go with it.
liberstina [14]
True. That is how powerful the sun is. But it will explode in only about 5 billion years.
6 0
4 years ago
A certain humidifier operates by raising water to the boiling point and then evaporating it. Every minute 30 g of water at 20◦ C
Sveta_85 [38]

Answer:

The value of total energy needed per minute for the humidifier = 77.78 KJ

Explanation:

Total energy per minute the humidifier required = Energy required to heat water to boiling point) + Energy required to convert liquid water into vapor at the boiling point) ----- (1)

Specific heat of water = 4190 \frac{J}{kg k}

The heat of vaporization is =  2256 \frac{KJ}{kg}

Mass = 0.030 kg

Energy needed to heat water to boiling point =  m c ( T_{2} - T_{1} )

Energy needed to heat water to boiling point = 0.030 × 4.19 × (100 - 20)

Energy (E_{1}) = 10.08 KJ

Energy needed to convert liquid water into vapor at the boiling point

E_{2} = 0.030 × 2256 = 67.68 KJ

Thus the total energy needed E =  E_{1} + E_{2}

E = 10.08 + 67.68

E = 77.78 KJ

This is the value of total energy needed per minute for the humidifier.

9 0
4 years ago
If =12a andthe distance from each wire to point p is 0.12m, then what is the magnitude of the magnetic force per unit length on
vaieri [72.5K]

The magnitude of the magnetic force per unit length on the top wire is

2×10⁻⁵  N/m

<h3>How can we calculate the magnitude of the magnetic force per unit length on the top wire ?</h3>

To calculate the magnitude of the magnetic force per unit length on the top wire, we are using the formula

F= \frac{\mu_0 I_f}{2\pi d}

Here we are given,

\mu_0= magnetic permeability

= 4\pi×10⁻⁷ H m⁻¹

If= 12 A

d= distance from each wire to point.

=0.12m

Now we put the known values in the above equation, we get

F= \frac{\mu_0 I_f}{2\pi d}

Or, F = \frac{4\pi \times 10^{-7}\times  12}{2\pi \times 0.12}

Or, F= 2×10⁻⁵ N/m.

From the above calculation, we can conclude that the magnitude of the magnetic force per unit length on the top wire is 2×10⁻⁵ N/m.

Learn more about magnetic force:

brainly.com/question/2279150

#SPJ4

7 0
2 years ago
Which is an example of something heated by conduction
hodyreva [135]
An example would be a pot on a stove. The radiation from the source of the heat (the stove) would make the handle hot by conduction from heat through contact.

Another example could be a metal spoon in a hot cup of coffee. The coffee itself is hot, but since the spoon is in the coffee and making contact, part of the spoon will become hot from the radiation of the source of heat (the hot coffee). Thus, conduction.
5 0
3 years ago
Suppose there was a star with a parallax angle of 1 arcsecond. How far away would it be? Select all that apply.
lesya692 [45]

Answer:

option E

Explanation:

given,                          

Parallax angle(d) = 1 arcsecond

using Parallax formula                  

      d = \dfrac{1}{p}

 p is the parsecs angle which is measured in 1 arcsecond

 d is the distance in parsec

now,                                            

      P = \dfrac{1}{d}

      P = \dfrac{1}{1}

      P = 1 \ parsec

we know,                                  

    1 parsec = 3.26 light year

hence, the answer will be option E

6 0
4 years ago
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