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3 years ago

If an object experiences an impulse and stops, what is its final momentum?

Physics

1 answer:

____ [38]3 years ago

3 0

Answer:

Zero

Explanation:

Since momentum is a product of mass and velocity of an object, in this case when the object stops its final velocity is zero hence despite the magnitude of its mass, multiplied by zero the final momentum is equivalent to zero. However, in case after experiencing momentum its velocity reduces but doesn’t come to a rest, the momentum will have a value. For this question, the first case applies hence momentum value is zero.

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PLEASE HELP!!!

d1i1m1o1n [39]

Answer: 95.7 N

Explanation: The tension on the chandelier is equal to the its weight.

Weight is the force directed downwards and tension is the force exerted of the opposite side.

T = W of the chain + W of the chandelier

= m1( g) + m2 (g)

= 0.37 kg ( 9.8 m/s2) + 9.4 kg (9.8 m/s2)

= - 95.7 N it means the force is directed downwards

since tension is equal weight

T = 95.7 N

6 0

3 years ago

What is the weight of a column of air with cross-sectional area 4. 5 m^2 extending from earth's surface to the top of the atmosp

sineoko [7]

The weight of a column of air with cross-sectional area 4. 5 m^2 extending from earth's surface to the top of the atmosphere is, 4.56*10^5N.

To find the answer, we have to know about the pressure.

<h3>How to find the weight of a column of air?</h3>

As we know that the expression of pressure as,

$P=\frac{F}{A}$

where; F is the force, here it is equal to the weight of the air column, and A is the area of cross section.

It is given that, the air column is extending from earth's surface to the top of the atmosphere, thus, the pressure will be atmospheric pressure,

$P=1atm=1.013*10^5Pascals$

From this, the value of weight will be,

$F=mg=P*A=1.013*10^5*4.5=4.56*10^5N$

Thus, we can conclude that, the weight of a column of air with cross-sectional area 4. 5 m^2 extending from earth's surface to the top of the atmosphere is, 4.56*10^5N.

Learn more about the pressure here:

brainly.com/question/12830237

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4 0

2 years ago

A rectangular flat coil moves at constant speed through a uniform magnetic field. The direction of the field is into the plane o

alukav5142 [94]

Answer:

The induced current will flow in a direction north of the plane of the paper

Explanation:

This is in compliance with faraday's right hand rule pictured below.

3 0

3 years ago

Two parallel metal plates are at a distance of 8.00 m apart.The electric field between the plates is uniform directed towards th

yuradex [85]

Answer:

Explanation:

Formula E=F/C also E=V/d

In this case use the second formula; E=V/d

Data given; E=4N/C d=8m

So v=E X d

V=4x8=32V

k.e=eV= 2X32=64eV

3 0

4 years ago

Complete the following:

masha68 [24]

When light is incident parallel to the principal axis and then strikes a lens, the light will refract through the focal point on the opposite side of the lens.

To find the answer, we have to know about the rules followed by drawing ray-diagram.

<h3>What are the rules obeyed by light rays?</h3>

If the incident ray is parallel to the principal axis, the refracted ray will pass through the opposite side's focus.
The refracted ray becomes parallel to the major axis if the incident ray passes through the focus.
The refracted ray follows the same path if the incident light passes through the center of the curve.

Thus, we can conclude that, when light is incident parallel to the principal axis and then strikes a lens, the light will refract through the focal point on the opposite side of the lens.

Learn more about refraction by a lens here:

brainly.com/question/13095658

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8 0

2 years ago