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shepuryov [24]
3 years ago
10

If an object experiences an impulse and stops, what is its final momentum?

Physics
1 answer:
____ [38]3 years ago
3 0

Answer:

Zero

Explanation:

Since momentum is a product of mass and velocity of an object, in this case when the object stops its final velocity is zero hence despite the magnitude of its mass, multiplied by zero the final momentum is equivalent to zero. However, in case after experiencing momentum its velocity reduces but doesn’t come to a rest, the momentum will have a value. For this question, the first case applies hence momentum value is zero.

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An athlete wants to refill an old punching bag used for training, as shown in the picture. When refilled, the bag will rip if it
In-s [12.5K]

The maximum force that the athlete exerts on the bag is NEGATIVE 1,500 N and in the OPPOSITE DIRECTION of the force that the bag exerts on the athlete.

<h3>Newton's third law of motion</h3>

Newton's third law of motion states action and reaction are equal and opposite. That is the force applied to an object is equal in magnitude to force experienced by the object but in opposite direction.

From the given question, when the bag exert a certain on the athlete, the athlete also exerts similar force to the bag but in opposite direction.

Thus, the complete sentence is as follows;

The maximum force that the athlete exerts on the bag is NEGATIVE 1,500 N and in the OPPOSITE DIRECTION of the force that the bag exerts on the athlete.

Learn more about Newton's third law of motion here: brainly.com/question/25998091

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5 0
2 years ago
Average amount of time wind machines operate
Rasek [7]

The wind machine on an average operates for a time of about \boxed{3-4\text{ hours}}.

Explanation:

The wind energy is the method of using the energy carried by the wind to generate the power. The wind energy is the considered as the conventional  and clean source of energy.

The wind machines require the high power winds to rotate the blades of the windmill and produce power using the energy of the moving wind.

The winds blow at such high speed for a very small time during the day, the wind machine cannot be expected to work for a longer time during the whole day.

The wind energy can be obtained form a wind mill for a limited time unlike the other form of energy like thermal energy or even the solar energy. The thermal energy can be obtained at anytime due to burning of fuel whereas the solar energy can at least be obtained during the whole day time.

Thus, the wind machine on an average operates for a time of about \boxed{3-4\text{ hours}}.

Learn More:

1. Acceleration of the box under friction brainly.com/question/7031524

2. The kinetic energy of an object depends on the brainly.com/question/137098

3. The approximate time taken to walk for 2000 miles brainly.com/question/3785992

Answer Details:

Grade: Middle School

Subject: Physics

Chapter: Energy

Keywords:

wind energy, conventional source, energy, thermal, solar, 3-4 hours, high speed, machine, time, operate.

6 0
3 years ago
PLS HELP! VERY URGENT! Choose three answers in the question below. I will give five stars the thanks and BRAINLIEST! I will give
Jet001 [13]

Answer:

sawing a board in half

dissolving sugar in water

a block of ice subliming

Explanation:

6 0
2 years ago
Read 2 more answers
What is the frequency of radiation whose wavelength is 11.5 a0 ?
irakobra [83]

Answer:

The frequency of radiation is 2.61 \times 10^{17} s^{-1}

Explanation:

Given:

Wavelength \lambda = 11.5 \times 10^{-10} m

Speed of light c = 3 \times 10^{8} \frac{m}{s}

For finding the frequency of radiation,

  c = f \lambda

  f = \frac{c}{\lambda}

  f = \frac{3 \times 10^{8} }{11.5 \times 10^{-10} }

  f = 2.61 \times 10^{17} s^{-1}

Therefore, the frequency of radiation is 2.61 \times 10^{17} s^{-1}

4 0
3 years ago
Two hockey pucks, labeled A and B, are initially at rest on a smooth ice surface and are separated by a distance of 18.0 m . Sim
Nonamiya [84]

Answer:

The distance covered by puck A before collision is  z = 8.56 \ m

Explanation:

From the question we are told that

   The label on the two hockey pucks is  A and  B

    The distance between the  two hockey pucks is D   18.0 m

     The speed of puck A is  v_A =  3.90 \ m/s

        The speed of puck B is  v_B  =  4.30 \ m/s

The distance covered by puck A is mathematically represented as

     z =  v_A * t

  =>  t  =  \frac{z}{v_A}

 The distance covered by puck B  is  mathematically represented as

      18 - z =  v_B  * t

=>   t  = \frac{18 - z}{v_B}

Since the time take before collision is the same

        \frac{18 - z}{V_B}  =  \frac{z}{v_A}

substituting values

          \frac{18 -z }{4.3}  = \frac{z}{3.90}

=>      70.2 - 3.90 z   = 4.3 z

=>       z = 8.56 \ m

8 0
3 years ago
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