1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Y_Kistochka [10]
3 years ago
9

What's a good way to determine the net force of something

Physics
1 answer:
ollegr [7]3 years ago
3 0
By adding up all the individual forces of the object
You might be interested in
A −3.0 nC charge is on the x-axis at x=−9 cm and a +4.0 nC charge is on the x-axis at x=16 cm. At what point or points on the y-
alexdok [17]

Answer:

y = 10.2 m

Explanation:

It is given that,

Charge, q_1=-3\ nC

It is placed at a distance of 9 cm at x axis

Charge, q_2=+4\ nC

It is placed at a distance of 16 cm at x axis

We need to find the point on the y-axis where the electric potential zero. The net potential on y-axis is equal to 0. So,

\dfrac{kq_1}{r_1}+\dfrac{kq_2}{r_2}=0

Here,

r_1=\sqrt{y^2+9^2} \\\\r_2=\sqrt{y^2+15^2}

So,

\dfrac{kq_1}{r_1}=-\dfrac{kq_2}{r_2}\\\\\dfrac{q_1}{r_1}=-\dfrac{q_2}{r_2}\\\\\dfrac{-3\ nC}{\sqrt{y^2+81} }=-\dfrac{4\ nC}{\sqrt{y^2+225} }\\\\3\times \sqrt{y^2+225}=4\times \sqrt{y^2+81}

Squaring both sides,

3\times \sqrt{y^2+225}=4\times \sqrt{y^2+81}\\\\9(y^2+225)=16\times (y^2+81)\\\\9y^2+2025=16y^2-+1296\\\\2025-1296=7y^2\\\\7y^2=729\\\\y=10.2\ m

So, at a distance of 10.2 m on the y axis the electric potential equals 0.

8 0
3 years ago
Any 3 differences between telescope and microscope
Keith_Richards [23]
An instrument used to observe or imagine very small object using an optical mangifier
mirco cell.
Telescope is a magnifer of distance object
4 0
3 years ago
Enny and Anne wanted to see who could throw a ball the hardest. They decided to each throw a ball against a wall as hard as they
mihalych1998 [28]

Answer:

wha t kind of variables

independent variables

dependent variables

controled variables

4 0
2 years ago
Where are globular clusters located in the milky way?.
mel-nik [20]

Answer:

Globular star clusters are located in the great spherical halo.

Explanation:

Hope this helps! :)

8 0
2 years ago
Compare the time period of two simple pendulums of length 4m and 16m at a place.
Vlad1618 [11]

Answer:

the period of the 16 m pendulum is twice the period of the 4 m pendulum

Explanation:

Recall that the period (T) of a pendulum of length (L)  is defined as:

T=2\,\pi\,\sqrt{ \frac{L}{g} }

where "g" is the local acceleration of gravity.

SInce both pendulums are at the same place, "g" is the same for both, and when we compare the two periods, we get:

T_1=2\,\pi\,\sqrt{\frac{4}{g} } \\T_2=2\,\pi\,\sqrt{\frac{16}{g} } \\ \\\frac{T_2}{T_1} =\sqrt{\frac{16}{4} } =2

therefore the period of the 16 m pendulum is twice the period of the 4 m pendulum.

5 0
3 years ago
Other questions:
  • A car speeds up from 12.0 m/s to 16.0 m/s in 8.0 s. the acceleration of the car is?
    15·1 answer
  • An alloy that contains mainly copper and tin is
    5·1 answer
  • 2001240Determine the specific kinetic energy of a mass whose velocity is 40 m/s, in kJ/kg.
    12·1 answer
  • How does a crowbar work?
    11·1 answer
  • A woman stands on a bathroom scale in a motionless elevator. When the elevator begins to move, the scale briefly reads only 0.79
    10·1 answer
  • How would the path of the ball differ on Earth than on the moon?Which statement best compares the accelerations of two objects i
    8·1 answer
  • First to answer will be the brainliest I need the answer ASAP don't answer if you don't know the answer
    10·2 answers
  • A rectangular plate is rotating with a constant angular speed about an axis that passes perpendicularly through one corner, as t
    11·1 answer
  • I REALLY NEED HELP!!!!
    9·1 answer
  • I need help to build a mouse trap race car for my science class and this is my final and these are the materials I have.
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!