Answer:
k[A][B][C]
Explanation:
Initial [A], mol/L Initial [B], mol/L Initial [C], mol/L Initial rate, mol/L.s
1 0.0500 0.0500 0.0100 6.25 x 10-3
2 0.100 0.0500 0.0100 1.25 x 10-2
3 0.100 0.100 0.0100 2.50 x 10-2
4 0.0500 0.0500 0.0200 1.25 x 10-2
Comparing equations 1 and 2, the reaction is first order with respect to A. This is because the concentration of A doubles, while the concentration of B and C remained constant leading to a double of the rate of reaction.
Comparing equations 2 and 3, the reaction is first order with respect to B. This is because the concentration of B doubles, while the concentration of A and C remained constant leading to a double of the rate of reaction.
Comparing equations 1 and 4, the reaction is first order with respect to C. This is because the concentration of C doubles, while the concentration of A and B remained constant leading to a double of the rate of reaction.
This means our rate law = k[A][B][C];
That is first order with respect to A, B and C
