In the presence of Hg (OAc)2, the alkenes reacts with alcohol to give allkoxy-mercurated product followed by reduction with NaBH4 to give ether. This reaction is known as alkoxymercuration-demercuration reaction.
8. Calculate the number of moles of eachsubstance.a. 5.45 x 1026 particles of methane, CH4
1 answer:
<em>ANSWER</em>
The number of moles of methane is 905.32 moles
STEP-BY-STEP EXPLANATION:
Given information
The number of particles of methane = 5.45 x 10^26 particles
Let x represents the number of moles of methane
To calculate the number of moles, we will be using the below formula
Recall that, the Avogadro's constant is given as
Therefore, the number of moles of methane is 905.32 moles
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ANs: [A] = [B] = 0.094 M
The following reaction was monitored as a function of time:
AB --> A + B
A plot of 1/[AB] versus time is a straight line with slope, K = 5.5×10^−2 M * s.
Now,
![\frac{1}{[AB]} = \frac{1}{[AB_{0} ]} + kT \\ \\ \frac{1}{[AB]} = \frac{1}{0.210} + (5.5* 10^{-2})*70 sec \\ \\ \\ \[AB] = 0.116](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B%5BAB%5D%7D%20%3D%20%5Cfrac%7B1%7D%7B%5BAB_%7B0%7D%20%5D%7D%20%2B%20kT%20%5C%5C%20%5C%5C%20%5Cfrac%7B1%7D%7B%5BAB%5D%7D%20%3D%20%5Cfrac%7B1%7D%7B0.210%7D%20%2B%20%285.5%2A%2010%5E%7B-2%7D%29%2A70%20sec%20%5C%5C%20%5C%5C%20%5C%5C%20%5C%5BAB%5D%20%3D%200.116)
<span>Now, Since at 70 s, [AB] = 0.116 M,
then amount of AB lost: </span>
<span>0.210 M - 0.116 M = 0.094 M
</span>
Now, according to the stoichiometry of the reaction,
<span>AB : A : B = 1 : 1 : 1,
</span>
<span>so both [A] and [B] gained the same number of moles and thus have same concentration, as [AB] lost.
So, [A] = [B] = 0.094 M after 70 s.</span>
The following reaction was monitored as a function of time:
AB --> A + B
A plot of 1/[AB] versus time is a straight line with slope, K = 5.5×10^−2 M * s.
Now,
<span>Now, Since at 70 s, [AB] = 0.116 M,
then amount of AB lost: </span>
<span>0.210 M - 0.116 M = 0.094 M
</span>
Now, according to the stoichiometry of the reaction,
<span>AB : A : B = 1 : 1 : 1,
</span>
<span>so both [A] and [B] gained the same number of moles and thus have same concentration, as [AB] lost.
So, [A] = [B] = 0.094 M after 70 s.</span>