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Sauron [17]
1 year ago
13

8. Calculate the number of moles of eachsubstance.a. 5.45 x 1026 particles of methane, CH4

Chemistry
1 answer:
Klio2033 [76]1 year ago
6 0

<em>ANSWER</em>

The number of moles of methane is 905.32 moles

STEP-BY-STEP EXPLANATION:

Given information

The number of particles of methane = 5.45 x 10^26 particles

Let x represents the number of moles of methane

To calculate the number of moles, we will be using the below formula

\text{Number of particles = number of moles x Avogadro's constant}

Recall that, the Avogadro's constant is given as

6.02\cdot10^{23}\begin{gathered} 5.45\cdot10^{26}\text{ = x }\cdot\text{ 6.02 }\cdot10^{23} \\ \text{Divide both sides by 6.02 }\cdot10^{23} \\ x\text{ = }\frac{5.45\cdot10^{26}}{6.02\cdot10^{23}} \\ x\text{ = }\frac{5.45}{6.02}\cdot10^{26\text{ - 23}} \\ x\text{ = 0.9053 }\cdot10^3 \\ x\text{ = 905.32 moles} \end{gathered}

Therefore, the number of moles of methane is 905.32 moles

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Vladimir79 [104]

Answer:

5.471% As₂O₃ in the sample.

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<em />

First, with the amount of KSCN we can find the moles of Ag in the filtrates. As we know the amount of Ag added we can know the precipitate of Ag and the moles of AsO₄ = 1/2 moles of As₂O₃ in the sample:

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0.0031564 - 0.001127 = 0.0020294 moles Ag⁺

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0.0020294 moles Ag⁺ * (1mol As / 3 moles Ag⁺) = 6.765x10⁻⁴ moles AsO₄

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6.765x10⁻⁴ moles AsO₄ * (1 mol As₂O₃ / 2 mol AsO₄) =

3.382x10⁻⁴ moles As₂O₃

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3.382x10⁻⁴ moles As₂O₃ * (197.84g/mol) = 0.0669g As₂O₃

Percent is:

0.0669g As₂O₃ / 1.223g sample * 100 =

<h3>5.471% As₂O₃ in the sample</h3>

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7 0
3 years ago
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Answer:

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Molar mass of chlorine = (35.5*2)

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Mass = 55.3 g of chlorine.

Number of moles = 55.3/71

= 0.779 moles.

8 0
3 years ago
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