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Marina86 [1]
3 years ago
6

If this element loses

Chemistry
1 answer:
Lorico [155]3 years ago
7 0

Answer:

KEDal

Explanation:

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What is thr pH of a solution of NaCl that has [H+] = 1.00 × 10-7 M
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3 0
3 years ago
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Balance each of the following redox reactions occurring in acidic aqueous solution.
dmitriy555 [2]

Answer:

Part A : Zn(s) + Sn²⁺(aq) → Zn²⁺(aq) + Sn(s).

Part B : 3Mg(s) + 2Cr³⁺(aq) → 3Mg²⁺(aq) + 2Cr(s).

Part C: 3MnO₄⁻ + 24H⁺ + 5Al → 5Al³⁺ + 3Mn²⁺ + 12H₂O.

Explanation:

<em>Part A : Zn(s) + Sn²⁺(aq) → Zn²⁺(aq) + Sn(s), Express your answer as a chemical equation. Identify all of the phases in your answer. </em>

  • It is balanced as written: Zn(s) + Sn²⁺(aq) → Zn²⁺(aq) + Sn(s).

The two half reactions are:

The oxidation reaction: Zn(s) → Zn²⁺(aq) + 2e.

The reduction reaction: Sn²⁺(aq) + 2e → Sn(s).

  • To obtain the net redox reaction, we add the two-half reactions as the no. of electrons in the two-half reactions is equal.

So, the net chemical equation is:

<em>Zn(s) + Sn²⁺(aq) → Zn²⁺(aq) + Sn(s).</em>

<em>Part B: Mg(s) + Cr³⁺(aq) → Mg²⁺(aq) + Cr(s), Express your answer as a chemical equation. Identify all of the phases in your answer. </em>

  • To balance and write the net chemical equation, we should write the two-half reactions:

The two half reactions are:

The oxidation reaction: Mg(s) → Mg²⁺(aq) + 2e.

The reduction reaction: Cr³⁺(aq) + 3e → Cr(s).

  • To obtain the net redox reaction, we multiply the oxidation reaction by 3 (3Mg(s) → 3Mg²⁺(aq) + 6e) and the reduction reaction by 2 (2Cr³⁺(aq) + 6e → 2Cr(s)) to equalize the no. of electrons in the two-half reactions.

So, the net redox reaction will be:

<em>3Mg(s) + 2Cr³⁺(aq) → 3Mg²⁺(aq) + 2Cr(s).</em>

<em>Part C : MnO⁴⁻(aq) + Al(s) → Mn²⁺(aq) + Al³⁺(aq), Express your answer as a chemical equation. Identify all of the phases in your answer.</em>

  • To balance and write the net chemical equation, we should write the two-half reactions:

The two half reactions are:

The oxidation reaction: Al → Al³⁺ + 3e.

The reduction reaction: MnO₄⁻ + 8H⁺ + 5e → Mn²⁺ + 4H₂O.

  • To obtain the net redox reaction, we multiply the oxidation reaction by 5 (5Al → 5Al³⁺ + 15e) and the reduction reaction by 3 (3MnO₄⁻ + 24H⁺ + 15e → 3Mn²⁺ + 12H₂O) to equalize the no. of electrons in the two-half reactions.

So, the net redox reaction will be:

<em>3MnO₄⁻ + 24H⁺ + 5Al → 5Al³⁺ + 3Mn²⁺ + 12H₂O.</em>

4 0
3 years ago
Suppose protons were emitted rather than electrons. How would this affect the experiment?
Vera_Pavlovna [14]

Suppose protons were emitted rather than electrons then it affects the experiment as the mean velocity of proton will be less then mean velocity electron .

The mass of proton is greater than the mass of electrons but charge of electron is equal to the charge of proton . So , due to difference in the mass of electron and proton there will be some effects.  We can conserve the electric energy which is equal to the qe .

The kinetic energy = 1/2mv^{2}

Now changing the electric potential energy into kinetic energy

v = √2qe/m

The mean velocity of proton will be less then mean velocity electron .

To learn more about proton

brainly.com/question/1252435

#SPJ4

6 0
2 years ago
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