Emissions of SO2 generated during the combustion of fossil fuels can be reduced<span> by treating the flue gases before they are emitted into the atmosphere via the stack; this is termed Flue Gas Desulphurisation (FGD). Flue gas desulphurisation systems can be classified as either Regenerable or Non-regenerable.
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The question is incomplete; the complete question is;
A chemist must dilute 99.4 mL of 152 mM aqueous potassium dichromate (K_2Cr_2O_7) solution until the concentration falls to 55.0 mM He'll do this by adding distilled water to the solution until it reaches a certain final volume. Calculate this final volume, in liters. Be sure your answer has the correct number of significant digits.
Answer:
0.275 L
Explanation:
From C1V1 = C2V2
Where;
C1= initial concentration of the solution 152 × 10^-3 M
V1= initial volume of the solution = 99.4 × 10^-3 L
C2 = concentration after dilution = 55 × 10^-3 M
V2 = volume after dilution = the unknown
V2 = C1 V1/C2
V2 = 152 × 10^-3 × 99.4 × 10^-3 / 55 × 10^-3
V2 = 0.275 L
Answer:
The combined gas law states that the pressure of a gas is inversely related to the volume and directly related to the temperature. If temperature is held constant, the equation is reduced to Boyle's law. Therefore, if you decrease the pressure of a fixed amount of gas, its volume will increase.
Explanation:
Answer:
The yearly release of
into the atmosphere is
.
Explanation:

Annual production of CaO = 
Moles of CaO :

According to reaction, 1 mole of CaO is produced along with 1 mole of carbon-dioxide.
Then along with
of CaO moles of carbon-dioxide moles produced will be:
of carbon-dioxide
Mass of
moles of carbon-dioxide:

The yearly release of
into the atmosphere is
.
Answer:
We'll have 13.85 grams of potassium
Explanation:
Step 1: Data given
Moles KBr = 0.46 mol
Molar mass KBr = 119.00 g/mol
Molar mass K = 30.10 g/mol
Step 2: The balanced equation
2KBr ⇆ 2K + Br2
Step 3: Calculate moles of K
For 2 moles KBr consumed we'll have 2 moles K and 1 mol Br2
For 0.46 moles KBr we'll have 0.46 moles K
Step 4: Calculate mass of K
Mass K = moles K * molar mass K
Mass K = 0.46 moles * 30.10 g/mol
Mass K = 13.85 grams
We'll have 13.85 grams of potassium