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Alja [10]
3 years ago
15

A. An FM radio station broadcasts at a frequency of 101.3 MHz. What is the wavelength?

Physics
1 answer:
Verdich [7]3 years ago
4 0

Answer:

a) \lambda = \frac{3x10^8 m/s}{101300000 Hz}= 2.962 m

b)  f= \frac{343 m/s}{2.962 m}= 115.8 Hz

Explanation:

For this case we have the following frequency given:

f= 101.3 MHz

We can convert this into Hz like this:

f= 101.3 MHz * \frac{10^6 Hz}{1 MHz}= 101300000 Hz

If we have a fundamental wave we need to satisfy the following condition:

v = \lambda f

If we solve for the wavelength we got:

\lambda = \frac{v}{f}

We know that the velocity of the light is v= 3x10^8 m/s

And if we replace into the last formula we got:

\lambda = \frac{3x10^8 m/s}{101300000 Hz}= 2.962 m

Part b

For this case we can use the same formula but on this case the velocity of the sound at 20C is approximately 343 m/s, the frequency is given by:

f = \frac{v}{\lambda}

We use the same wavelenght from the previous part \lamba = 2.962 m

And if we replace the new values we got:

f= \frac{343 m/s}{2.962 m}= 115.8 Hz

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7 0
3 years ago
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A baseball with a mass of 151 g is thrown horizontally with a speed of 40.3 m/s (90 mi/h) at a bat. The ball is in contact with
Ghella [55]

Answer:

A baseball (m= 149g) approaches a bat horizontally at a speed of 40.2 m/s (90 mi/h) and is hit straight back at a speed of 45.6m/s (102mi/h). If the ball is in contact with the bat for a time of 1.10ms, what is the average force exerted on the ball by the bat ? Neglect the weight of the ball, since it is so much less than the force of the bat. Choose the direction of the incoming ball as the positive direction.

Explanation:

Use the impulse equation (a form of Newton's 2nd Law): FΔt = Δ(mv) where Δ means "change in"

The change in momentum is mBB(vf - vi) = (.150 kg)(-46.9 m/s - 40.5 m/s)

Divide this by the time interval and you get F exerted by the bat in Newtons.

Take care.

6 0
3 years ago
What work is done by the electric force when the charge moves a distance of 2.70 m at an angle of 45.0∘ downward from the horizo
Andreyy89

Incomplete question as many data is missing.I have assumed value of charge and electric field.The complete question is here

A charge of 28 nC is placed in a uniform electric field that is directed vertically upward and that has a magnitude of 5.00×10⁴ V/m.

What work is done by the electric force when the charge moves a distance of 2.70 m at an angle of 45.0 degrees  downward from the horizontal?

Answer:

W_{work}=2.67*10^{-3}J

Explanation:

Given data

Charge q=28 nC

Electric field E=5.00×10⁴ V/m.

Distance d=2.70 m

Angle α=45°

To find

Work done by electric force

Solution

W_{work}=F_{force}*D_{distance}Cos\alpha  \\where\\F_{force}=q_{charge}*E_{Electric-Field}\\So\\W_{work}=qE*D*Cos\alpha \\W_{work}=(28*10^{-9}C )(5.00*10^{4}V/m )(2.70m)Cos(45)\\W_{work}=2.67*10^{-3}J

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3 years ago
Help? its due in like 12 minutes lolzz
Gnom [1K]

Answer:

Question 1: the plates are moving toward one another.

Question 2: The Himalayan Mountains in India

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The paragraph explains that the plates continue to move closer to one another while forming multiple mountains.

The paragraph explains, " a well-known example of this is the formation of the Himalayan Mountains in India,"

The area of the Himalayan Mountains are better suited for the formation of mountains rather than volcanoes.

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4 0
3 years ago
A diver springs upward from a board that is 4.40 m above the water. At the instant she contacts the water her speed is 13.5 m/s
Yakvenalex [24]

The diver has the initial velocity, both (a) magnitude is 9.8 m/s and (b) direction is  73.5°.

<h3>What is free falling?</h3>

When an object is released from rest in free air considering no friction, the motion is depend only on the acceleration due to gravity, g.

If we drop an object of mass m near the Earth surface from a height h, it has initial mechanical energy(P.E)

U =mgh

When the object strikes the ground, all the potential energy converted into kinetic energy.

K.E = 1/2mv²

where v is the speed just before hitting the ground.

A diver springs upward from a board that is 4.40 m above the water. At the instant, she contacts the water her speed is 13.5 m/s and her body makes an angle of 78.1 ° with respect to the horizontal surface of the water.

(a)

From energy conservation principle, initial and final mechanical energy are equal.

1/2mu² + mgh = 1/2mv²

where, u is the initial velocity of the diver.

u = sq rt  (v² - 2gh)

u = sq rt (13.5² - 2x9.81x4.4)

u = 9.798 m/s or 9.8 m/s

Thus, the velocity of the diver is 9.8 m/s.

(b)

The horizontal component of velocity will remain constant.

The horizontal component of acceleration is zero.

Then,

ucosθ = vcosΦ

θ = cos⁻¹ [ (13.5 x cos 78.1)/9.8 ]

θ = 73.5°

Thus, the direction of velocity is  73.5°.

Learn more about free falling.

brainly.com/question/13299152

#SPJ1

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2 years ago
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