Answer:
downwards bro now dodododododdodo
The skateboarder will have the greatest potential energy at point <em>G.</em>
Potential energy is the energy possessed by a body by virtue of its position. The gravitational potential energy of a body is given by the expression,
Here, <em>m</em> is the mass of the body, <em>g</em> the acceleration due to gravity and <em>h</em> is the height of the body from the ground.Thus as <em>h</em> increases, the potential energy increases.
From the figure, it can be seen that the highest point in the skateboarder's trajectory is <em>G.</em> hence, he would have the highest potential energy at the point <em>G.</em>
Decreases
Explanation:
The acceleration due to gravity on a body decreases with depth.
Acceleration due to gravity is the change in velocity with time of a body as result of the pull of gravity or gravitational force.
- The acceleration due to gravity tend to pull all bodies to the center of the earth.
- As body moves away from the center of the earth, the pull becomes very more and acceleration increase.
- But when a body approaches the center of the earth, the acceleration reduces.
- At depth, the acceleration due to body of a body begins to decrease.
learn more:
Gravity brainly.com/question/10934170
#learn more brainly.com/question/10934170
#learnwithBrainly
Answer:
0.705 m/s²
Explanation:
a) The sprinter accelerates uniformly from rest and reaches a top speed of 35 km/h at the 67-m mark.
Using newton's law of motion:
v² = u² + 2as
v = final velocity = 35 km/h = 9.72 m/s, u = initial velocity = 0 km/h, s = distance = 67 m
9.72² = 0² + 2a(67)
134a = 94.484
a = 0.705 m/s²
b) The sprinter maintains this speed of 35 km/h for the next 88 meters. Therefore:
v = 35 km/h = 9.72 m/s, u = 35 km/h = 9.72 m/s, s = 88 m
v² = u² + 2as
9.72² = 9.72² + 2a(88)
176a = 9.72² - 9.72²
a = 0
c) During the last distance, the speed slows down from 35 km/h to 32 km/h.
u = 35 km/h = 9.72 m/s, v = 32 km/h = 8.89 m/s, s = 200 - (67 + 88) = 45 m
v² = u² + 2as
8.89² = 9.72² + 2a(45)
90a = 8.89² - 9.72²
90a = -15.4463
a = -0.1716 m/s²
The maximum acceleration is 0.705 m/s² which is from 0 to 67 m mark.
