Question

A steady electric current flows through a wire. If 9.0 C of charge passes a particular spot in the wire in a time period of 2.0 s, what is the current in the wire? 4.5 A 18 A 0.22 A 9.0 A If the current is a constant 3.0 A, how long will it take for 14.0 C of charge to move past a particular spot in the wire? 0.21 s 4.7 s 14.0 s 42 s

Answer 1

1) Current: 4.5 A

2) Time taken: 4.7 s

Explanation:

1)

The electric current intensity is defined as the rate at which charge flows in a conductor; mathematically:

$I=\frac{q}{t}$

where

I is the current

q is the amount of charge passing a given point in a time t

For the wire in this problem, we have

q = 9.0 C is the amount of charge

t = 2.0 s is the time interval

Solving for I, we find the current:

$I=\frac{9.0}{2.0}=4.5 A$

2)

To solve this problem, we can use again the same formula

$I=\frac{q}{t}$

where

I is the current

q is the amount of charge passing a given point in a time t

In this problem, we have:

I = 3.0 A (current)

q = 14.0 C (charge)

Therefore, the time taken for the charge to move past a particular spot in the wire is

$t=\frac{q}{I}=\frac{14.0}{3.0}=4.7 s$

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