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Triss [41]
3 years ago
11

photon energy is proportional to which of the following. a. speed of light in a vacuum. B frequency of the light emitting the ph

oton. C intensity of the light emmitting the photon. D wavelegnth of light emmitting thr photon.
Physics
1 answer:
avanturin [10]3 years ago
3 0
We have that according to the quantum theory from Planck, E=h*f where h is a constant and f is the frequency, thus B is correct. Let's analyze the other choices: The speed of light in vacuum is irrelevant to the energy of the photon. The instensity of a light source is correlated to the amount of photons in that light beam but it does not affect individual photons. Finally, if l is the wavelength of light, l*f=c. Substituting this in the first equation we see that photon energy is inversely proportional to the wavelength.
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Describe the wavelength of a longitudinal wave.
Lilit [14]
In Longitudinal waves, particles of the medium vibrate around their mean positions. Their amplitude of vibration is in the direction of the propagation of the wave. In transverse wave of longitudinal wave, <em>the wavelength is always the distance between two particles which are in the same phase.</em>

If we take pressure waves, (sound waves), we have pressure variations created by sound wave along its path. Pressure is maximum at compression regions and pressure is minimum at rarefaction region. In between the two, pressure of air remains as the pressure when there is no wave.

<em>The wave length is then the distance between two consecutive rarefactions or two consecutive compression regions.</em>

<em>It is also the distance traveled by the wave in one time period.</em> Time period is the time the particles in the medium take to vibrate towards the end, turn back to reach the other end of their oscillation and then reach back their position.


6 0
3 years ago
Which object represents a negatively charged particle? which object represents a positively charged molecule? which object repre
kari74 [83]

The answers to your questions are as written below:

  • The objects that represents a negatively charged particle is : Image B
  • The object that represents a positively charged molecule is : Image A
  • The object that represents an uncharged molecule is : Image C
  • The object the will not move when in an electric fied is : Image C

<h3>Different types of charges molecules</h3>

A negatively charged molecule move inwards when placed in an electric field while positively charged molecule placed in a electric field will move outwards the electric field.

A neutral/uncharged molecule will remains still when placd in an elctric field due to the absence of charges.

Hence we can concude that the answers to your questions are as listed above.

Learn more about electric charges :brainly.com/question/857179

#SPJ4

attached below is the missing image

8 0
2 years ago
An ideal gas at 27°C is contained in a piston that ensures that its pressure will always be constant. Raising the tem- perature
zlopas [31]

Answer:

T = 600K

Explanation:

See attachment below.

7 0
4 years ago
A 62 kg skier is moving at 6.5 m/s on frictionless horizontal snow-covered plateau when she encounters a rough patch 3.50 m long
Degger [83]

Answer:

(A). The work done by friction in crossing the patch is -637.98 J.

(B). The speed of skier is 10.57 m/s.

Explanation:

Given that,

Mass of skier = 62 kg

Speed = 6.5 m/s

Length = 3.50 m

Coefficient kinetic friction = 0.30

Height = 2.5 m

(A) we need to calculate the work done by friction in crossing the patch

Using formula of work done

W=-\mu mg\times l

Put the value into the formula

W=-0.30\times62\times9.8\times3.50

W=-637.98\ J

The work done by friction in crossing the patch is -637.98 J.

(B) we need to calculate the speed of skier

Using conservation of energy

K.E_{i}+U_{i}-W_{friction}=K.E_{f}+U_{f}

\dfrac{1}{2}mv_{1}^2+mgh-\mu mgl=\dfrac{1}{2}mv_{2}^2+U_{f}

Final potential energy is zero

So, \dfrac{1}{2}mv_{1}^2+mgh-\mu mgl=\dfrac{1}{2}mv_{2}^2

\dfrac{1}{2}v_{2}^2=\dfrac{1}{2}v_{1}^2+gh-\mu gl

Put the value into the formula

\dfrac{1}{2}v_{2}^2=\dfrac{1}{2}\times6.5^2+9.8\times2.5+0.30\times9.8\times3.50

v_{2}=\sqrt{2\times55.915}

v_{2}=10.57\ m/s

The speed of skier is 10.57 m/s.

Hence,  (A).The work done by friction in crossing the patch is -637.98 J.

(B).The speed of skier is 10.57 m/s.

6 0
3 years ago
A ball is tossed up into the air, reaches its highest point and returns to its original position. which of the following is true
Gekata [30.6K]

Answer: (Projectile motion)

Option A — At its highest point the ball’s velocity is 0 and so it it’s acceleration (0).

This is because at the highest point, the ball’s direction changes. This is due to the forces counteracting the upward momentum (mass*velocity) of the ball, so the ball slows down and when it reaches it highest point starts to change direction and fall back down. In the short period of time at which its at its highest point, it’s velocity reaches 0 for a very short amount of time, and so does its acceleration.

3 0
3 years ago
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