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galina1969 [7]
3 years ago
6

g Glycolysis is the process by which energy is harvested from glucose by living things. Several of the reactions of glycolysis a

re thermodynamically unfavorable (nonspontaneous), but proceed when they are coupled with other reactions. Reaction A: Pi+glucose⟶glucose-6-phosphate+H2OΔ????=13.8 kJ/mol Reaction B: Pi+fructose-6-phosphate⟶fructose-1,6-bisphosphate+H2OΔ????=16.3 kJ/mol Reaction C: ATP+H2O⟶ADP+PiΔ????=−30.5 kJ/mol Select every unfavorable reaction. reaction A reaction C reaction B
Chemistry
1 answer:
Alex787 [66]3 years ago
6 0

Answer:

A and B are unfavorable reactions.

Explanation:

In chemical thermodynamics, an endergonic reaction  is also called a nonspontaneous reaction or an unfavorable reaction. it's a chemical reaction in which the change in free energy is positive, and energy is absorbed.

In chemical thermodynamics, an exergonic reaction  is also called a spontaneous reaction or a favorable reaction. it's a chemical reaction in which the change in free energy is negative.

ΔG>0

If the Gibbs  free energy of the reaction is positive than the reaction will be non spontaneous .

If the Gibbs  free energy of the reaction is negative than the reaction will be spontaneous

Gibbs free energy is an energy which that can be use to convert into useful work.

ΔG=ΔH-TΔS

with ΔG= Gibbs free energy

with ΔH =  enthalpy of reaction

with T = temperature of eh reaction

ΔS = Entropy change

The reaction A: Pi+glucose⟶glucose-6-phosphate+H2O

The ΔG is positive. This is an nonspontaneous reaction or an unfavorable reaction

The reaction B: Pi+fructose-6-phosphate⟶fructose-1,6-bisphosphate+H2O

The ΔG is positive. This is an nonspontaneous reaction or an unfavorable reaction.

The reaction C: ATP+H2O⟶ADP+Pi

The ΔG is negative. This is a spontaneous reaction or a favorable reaction.

A and B are unfavorable reactions.

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What is the [H+] of a solution with a pH of 9.40?
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Answer:

a) 3.98 x 10^-10

Explanation:

Hello,

In this case, for the given pH, we can compute the concentration of hydronium by using the following formula:

pH=-log([H^+])

Hence, solving for the concentration of hydronium:

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If the amount of dissolved solute in a solution at a given temperature is greater than the amount that can permanently remain in
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d. supersaturated.

Explanation:

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However, when the amount of dissolved solute in a solution at a given temperature is greater than the amount that can permanently remain in the solution at that temperature, the solution is said to be SUPERSATURATED. This means that the solution contains more than the maximum amount of solute.

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What volume, in mL, of carbon dioxide gas is produced at STP by the decomposition of 0.242 g calcium carbonate (the products are
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Answer:

54.21 mL.

Explanation:

We'll begin by calculating the number of mole in 0.242 g calcium carbonate, CaCO3.

This is illustrated below:

Mass of CaCO3 = 0.242 g

Molar mass of CaCO3 = 40 + 12 +(16x3) = 40+ 12 + 48 = 100 g/mol

Mole of CaCO3 =?

Mole = mass /Molar mass

Mole of CaCO3 = 0.242/100

Mole of CaCO3 = 2.42×10¯³ mole.

Next, we shall write the balanced equation for the reaction. This is given below:

CaCO3 —> CaO + CO2

From the balanced equation above,

1 mole of CaCO3 decomposed to produce 1 mole CaO and 1 mole of CO2.

Next, we shall determine the number of mole of CO2 produced from the reaction.

This can be obtained as follow:

From the balanced equation above,

1 mole of CaCO3 decomposed to produce 1 mole of CO2.

Therefore,

2.42×10¯³ mole of CaCO3 will also decompose to produce 2.42×10¯³ mole of CO2.

Therefore, 2.42×10¯³ mole of CO2 were obtained from the reaction.

Finally, we shall determine volume occupied by 2.42×10¯³ mole of CO2.

This can be obtained as follow:

1 mole of CO2 occupies 22400 mL at STP.

Therefore, 2.42×10¯³ mole of CO2 will occupy = 2.42×10¯³ x 22400 = 54.21 mL

Therefore, 54.21 mL of CO2 were obtained from the reaction.

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