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ohaa [14]
4 years ago
8

A box contains equal amounts of helium, argon, and krypton (all gases) at 25 ∘c. part a consider the temperatures, masses, avera

ge velocities, and average kinetic energy of the three kinds of gas in the mixture. what do they have in common? what are the differences?
Chemistry
2 answers:
crimeas [40]4 years ago
8 0
1. What do they have in common?

As mentioned in the problem, these gases are present in equal amounts. So, that would infer that they are common in terms of their mass. Also, it is specified that the temperature is 25°C. Connected to that is the average kinetic energy, which is directly proportional. Hence, they are also common in temperature and average kinetic energy.

2. What are the differences?

They differ in type, of course. Also, they differ in average velocities which is a factor of temperature of molar mass. Since they are 3 different types of gases with different molar masses, they would also differ in their average velocities.
ANTONII [103]4 years ago
4 0

The common things in all gases are temperature, average kinetic energy, and average velocities. The different thing about the gases is their masses.

Further explanation:

The given gases are helium, argon, and krypton. It is also given in the question that all gases are in equal amount. The temperature of the box containing all gases is 25 oC.

Common in all gases:

Temperature: Since all gases are in the box at temperature 25 oC, therefore, the temperature is the same for all gases.

Average kinetic energy: The average kinetic energy of the gas is given as,

K=\frac{3}{2}\frac{R}{{{N_A}}}T

Here, <em>K</em> is average kinetic energy, <em>R</em> is a gas constant, {N_A} is an Avogadro’s number, and <em>T</em> is temperature (in Kelvin)

Since the average kinetic energy is only related to temperature and temperature of all gases is the same, and therefore, average kinetic energy is also the same for all gases.

Average velocities: Average velocity of gases is directly related to the kinetic energy and temperature of gases thus the average velocity is also the same for all gases.

Different in all gases:

Mass: The given quantity of gases is the same. This means the number of particle of each gas present in the box is same. But the mass of each gas is different because the molar mass of each gas is different.

Learn more:

1. Determine the Lewis structure of butanal.: brainly.com/question/6215269

2. Determine the reason that causes water molecule a bent shape.:brainly.com/question/1979769

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Ideal gas equation

Keywords: Ideal gas, helium, argon, krypton, temperature, masses, average velocities, average kinetic energy, gas in the mixture.

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Assuming that x \; \text{L} of the 0.307 \text{mol} \cdot \text{dm}^{-3} sodium hydroxide solution was added to the acetic acid. Based on previous reasoning, x is sufficiently small that acetic acid was in excess, and no hydroxide ion has yet been produced in the solution. The solution would thus contain 0.2000 \times 0.425 - 0.307 \; x = 0.085 - 0.307 \; x moles of acetic acid and 0.307 \; x moles of acetate ions.

Let \text{HAc} denotes an acetic acid molecule and \text{Ac}^{-} denotes an acetate ion. The RICE table below resembles the hydrolysis equilibrium going on within the buffer solution.

\begin{array}{lccccc}\text{R} & \text{HAc} & \leftrightharpoons & \text{H}^{+} & + & \text{Ac}^{-}\\\text{I} & 0.085 - 0.307 \; x& & 0 & & 0.307 \; x\\\end{array}

The buffer shall have a pH of 4.250, meaning that it shall have an equilibrium proton concentration of 10^{4.250}\; \text{mol}\cdot \text{dm}^{-3}. There were no proton in the buffer solution before the hydrolysis of acetic acid. Therefore the table shall have an increase of 10^{-4.250}\;\text{mol}\cdot \text{dm}^{-3} in proton concentration in the third row. Atoms conserve. Thus the concentration increase of protons by 10^{-4.250}\;\text{mol}\cdot \text{dm}^{-3} would correspond to a decrease in acetic acid concentration and an increase in acetate ion concentration by the same amount. That is:

\begin{array}{lcccccc}\text{R} & \text{HAc} & \leftrightharpoons & \text{H}^{+} & + & \text{Ac}^{-}\\\text{I} & 0.085 - 0.307 \; x& & 0 & & 0.307 \; x\\\text{C} & - 10^{-4.250} & & +10^{-4.250} & & +10^{-4.250} \\\text{E} & 0.085 - 10^{-4.250} - 0.307 \; x& & 10^{-4.250} & & 10^{-4.250} + 0.307 \; x\end{array}

By definition:

\text{K}_{a} = [\text{H}^{+}] \cdot [\text{Ac}^{-}] / [\text{HAc}]\\\phantom{\text{K}_{a}} = 10^{-4.250} \times (10^{-4.250} + 0.307 \; x) / (0.085 - 10^{-4.250} - 0.307 \; x)

The question states that

\text{K}_{a} = 1.75 \times 10^{-5}

such that

10^{-4.250} \times (10^{-4.250} + 0.307 \; x) / (0.085 - 10^{-4.250} - 0.307 \; x) = 1.75 \times 10^{-5}\\6.16 \times 10^{-5} \; x = 1.48 \times 10^{-6}\\x = 0.0241

Thus it takes 0.0241 \; \text{L} of sodium hydroxide to produce this buffer solution.

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