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4 years ago

Write this number in standard notation. 4.702 x 10–4

Physics

2 answers:

igor_vitrenko [27]4 years ago

8 0

Answer:

the answer is .0004702

iragen [17]4 years ago

6 0

Move the decimal three places to the left -> .0004702

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A nerve signal travels 150 meters per second. Determine the number of kilometers that the nerve signal will travel in the same t

joja [24]

Explanation:

It is given that,

A nerve signal travels 150 meters per second. It is the speed of the nerve signal. We need to convert the number of kilometers that the nerve signal will travel in the same time.

We know that,

1 kilometer = 1000 meter

1 hour = 3600 seconds

$150\ \dfrac{m}{s}=150\times \dfrac{1/1000\ km}{1/3600\ h}$

$150\ m/s=540\ km/h$

So, the nerve signal will travel at the rate of 540 km/h. Hence, this is the required solution.

6 0

3 years ago

Which statement most accurately describes the second law of thermodynamics?

balandron [24]

Answer:

Energy cannot be changed from one form to another without a loss of usable energy

Explanation:

Second law of thermodynamics states that the total entropy or the randomness of the system remains constant over time. It also states that the net entropy will remain the same or it will increase.

Entropy of a system is given by heat absorbed divided by temperature. It is given by :

$\Delta S=\dfrac{\Delta Q}{T}$

So, the correct option is (A) "Energy cannot be changed from one form to another without a loss of usable energy".

4 0

3 years ago

Two convex lenses are placed 15 cm apart. The left lens has a focal length of 10 cm, and the right lens a focal length of 5 cm.

Minchanka [31]

Answer:

The image distance from right lens is 2.86 cm and image is real.

Explanation:

Given that,

Focal length of left lens = 10 cm

Focal length of right lens = 5 cm

Distance between the lenses d= 15 cm

Object distance = 50 cm

We need to calculate the image distance from left lens

Using formula of lens

$\dfrac{1}{v}=\dfrac{1}{f}-\dfrac{1}{u}$

Put the value into the formula

$\dfrac{1}{v}=\dfrac{1}{10}-\dfrac{1}{-50}$

$\dfrac{1}{v}=\dfrac{3}{25}$

$v=8.33\ cm$

We need to calculate the image distance from right lens

The object distance will be

$u = 15-8.33 = 6.67\ cm$

Using formula of lens

$\dfrac{1}{v}=\dfrac{1}{f}-\dfrac{1}{u}$

Put the value into the formula

$\dfrac{1}{v}=\dfrac{1}{5}-\dfrac{1}{-6.67}$

$\dfrac{1}{v}=\dfrac{1167}{3335}$

$v=2.86\ cm$

The image is real.

Hence, The image distance from right lens is 2.86 cm and image is real.

4 0

3 years ago

If six moles of hydrogen chloride (HCl) react with plenty of aluminum, how many moles of aluminum chloride (AlCl3) will the reac

AlexFokin [52]

Answer:

Two moles of aluminum chloride $(AlCl_3)$ are produced when six miles of hydrogen Chloride $(HCl)$ react with plenty of aluminum

Explanation:

6 Moles of $HCl$ will only react with 2 moles of $Al$ irrespective of the number of moles of each compound present. The reaction wiil take place in this ratio only. The products produced will be 2 moles of $AlCl_3$ and 3 moles of $H_2$ this ratio will also be constant.