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velikii [3]
3 years ago
11

A golfer takes two putts to sink his ball in the hole. The first putt displaces the ball 6.50 m east, and the second putt displa

ces it 5.90 m south. What displacement would put the ball in the hole in one putt?
Physics
1 answer:
skad [1K]3 years ago
8 0
<h2>Displacement to hole from initial position is 8.78 m at direction 42.23° south of east.</h2>

Explanation:

Let east represent X axis and north represent Y axis.

We need to find what displacement would put the ball in the hole in one putt.

The first putt displaces the ball 6.50 m east

First displacement = 6.50 i m

The second putt displaces it 5.90 m south

Second displacement = -5.90 j m

Total displacement = 6.50 i - 5.90 j

\texttt{Magnitude = }\sqrt{6.50^2+(-5.90)^2}=8.78m\\\\\texttt{Direction = }tan^{-1}\left ( \frac{-5.9}{6.5}\right )=-42.23^0

So displacement to hole from initial position is 8.78 m at direction 42.23° south of east.

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v = 3.04 m/s

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