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3 years ago

calculate the linear momentum of a pickup truck that has a mass of 1000kg, and is traveling eastward at 20 m/s

2 answers:

ioda3 years ago

4 0

Momentum = Mass × Velocity

From the given data, Mass is 1000kg and Velocity is 20m/s

Momentum = 1000 × 20
$Momentum = 20000 {kgms}^{ - 1}$

Sloan [31]3 years ago

3 0

Answer:

The momentum of the truck is $2\times 10^4\ kg-m/s$ .

Explanation:

It is given that,

Mass of the truck, m = 1000 kg

Speed of the truck, v = 20 m/s (towards east)

Let p is the linear momentum of a truck. It is equal to the product of mass and velocity. Mathematically, it is given by :

p = m v

$p=1000\ kg\times 20\ m/s$

$p=2\times 10^4\ kg-m/s$

So, the linear momentum of the truck is $2\times 10^4\ kg-m/s$ . Hence, this is the required solution.

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A student discovers that sound waves travel 1,687.5 meters in 5 seconds through air at a temperature of 10°C. Based on this info

vitfil [10]

Answer:

The speed of sound, in m/s, through air at this temperature is 343.5 m/s

Explanation:

Given;

distance traveled by sound, d = 1,687.5 meters

time taken for the sound to travel, t = 5 seconds

air temperature, θ = 10°C

Speed of sound = distance traveled by sound / time taken for the sound to travel

Speed of sound = d / t

= 1687.5 m / 5 s

= 337.5 m/s

Speed of sound at the given temperature is calculated as;

c = 337.5 + 0.6θ

c = 337.5 + 0.6 x 10

c = 337.5 + 6

c = 343.5 m/s

Therefore, the speed of sound, in m/s, through air at this temperature is 343.5 m/s

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3 years ago

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3 years ago

A light-rail commuter train accelerates at a rate of 1.35 m/s. D A 33% Part (a) How long does it take to reach its top speed of

Dennis_Churaev [7]

Answer:

a) 17.49 seconds

b) 13.12 seconds

c) 2.99 m/s²

Explanation:

a) Acceleration = a = 1.35 m/s²

Final velocity = v = 85 km/h = $85\frac{1000}{3600}=23.61\ m/s$

Initial velocity = u = 0

Equation of motion

$v=u+at\\\Rightarrow 23.61=0+1.35t\\\Rightarrow t=\frac{23.61}{1.35}=17.49\ s$

Time taken to accelerate to top speed is 17.49 seconds.

b) Acceleration = a = -1.8 m/s²

Initial velocity = u = 23.61\ m/s

Final velocity = v = 0

$v=u+at\\\Rightarrow 0=23.61-1.8t\\\Rightarrow t=\frac{23.61}{1.8}=13.12\ s$

Time taken to stop the train from top speed is 13.12 seconds

c) Initial velocity = u = 23.61 m/s

Time taken = t = 7.9 s

Final velocity = v = 0

$v=u+at\\\Rightarrow 0=23.61+a7.9\\\Rightarrow a=\frac{-23.61}{7.9}=-2.99\ m/s^2$

Emergency acceleration is 2.99 m/s² (magnitude)

6 0

2 years ago

A woman holds a book by placing it between her hands such that she presses at right angles to the front and back covers. The boo

In-s [12.5K]

Answer:

Explanation:

In order to solve this problem we need to make a free body diagram of the book and the forces that interact on it. In the picture below you can see the free body diagram with these forces.

The person holding the book is compressing it with his hands, thus exerting a couple of forces of equal magnitude and opposite direction with value F.

Now the key to solving this problem is to analyze the equilibrium condition (Newton's third law) on the x & y axes.

To find the weight of the book we simply multiply the mass of the book by gravity.

W = m*g

W = 1.3[kg] * 9.81[m/s^2]

W = 12.75 [N]

7 0

2 years ago

A roller coaster car of mass m= 300 kg is released from rest at the top of a 60 m high hill (position A), and rolls with a negli

Andrews [41]

Answer: The principle of conservation of energy, angular speed and centripetal force

Explanation:

At point A, the car experienced maximum of potential energy

As it moves down the hill, the potential energy decreases while the kinetic energy increases.

The maximum kinetic energy of the car is needed for the attainment of enough centripetal force to help the car move through the loop without falling .

4 0

3 years ago