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swat32
3 years ago
15

A (11.4 A) ohm device is connected to a 115 V outlet. If the cost of the electrical energy is $0.16/kWh, determine the cost of r

unning this device for (36.0 B) hours. Round your answer in dollars ($) with 2 decimal places.
Physics
1 answer:
Scrat [10]3 years ago
4 0

Answer:

$6.68

Explanation:

The current running through the device would be its outlet voltage divided by the resistance:

I = U/R = 115 / 11.4 = 10.09 A

The power generated by this device is the product of its current and voltage

P = IU = 10.09 * 115 = 1160 W or 1.16 kW

If running this device for 36 hours then the total energy it would consume is

E = Pt = 1.16 * 36 = 41.76 kWh

Therefore the total cost of electrical energy is

C = Ec = 41.76*0.16 = $6.68

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A cosmic ray electron moves at 7.50×106 m/s perpendicular to the Earth’s magnetic field at an altitude where field strength is 1
wlad13 [49]

Answer:

4.266 m.

Explanation:

Given,

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4 0
3 years ago
Please just give me an answer, thanks.
Colt1911 [192]

#1

\\ \rm\dashrightarrow P=VI\implies V=\dfrac{P}{I}

\\ \rm\dashrightarrow V=\dfrac{0.4\times 10^3}{33\times 10^{-3}}

\\ \rm\dashrightarrow V=0.012\times 10^{-6}

\\ \rm\dashrightarrow V=12mV

#2

\\ \rm\dashrightarrow R=\rho \dfrac{\ell}{A}

\\ \rm\dashrightarrow \rho =\dfrac{RA}{\ell}

\\ \rm\dashrightarrow \rho=\dfrac{86.3(0.4\times 10^6)}{69}

\\ \rm\dashrightarrow \rho=0.5\times 10^{6}

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Ohms law

\\ \rm\dashrightarrow R=\dfrac{V}{I}

\\ \rm\dashrightarrow R=\dfrac{7(10^3)}{6(10^{-6})}

\\ \rm\dashrightarrow R=1.167\times 10^9\Omega

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