I think it’s speed will increase, if I understood it correctly
Answer:
d = 76.5 m
Explanation:
To find the distance at which the boats will be detected as two objects, we need to use the following equation:

<u>Where:</u>
θ: is the angle of resolution of a circular aperture
λ: is the wavelength
D: is the diameter of the antenna = 2.10 m
d: is the separation of the two boats = ?
L: is the distance of the two boats from the ship = 7.00 km = 7000 m
To find λ we can use the following equation:
<u>Where:</u>
c: is the speed of light = 3.00x10⁸ m/s
f: is the frequency = 16.0 GHz = 16.0x10⁹ Hz
Hence, the distance is:

Therefore, the boats could be at 76.5 m close together to be detected as two objects.
I hope it helps you!
D) Less than 20.
Explanation:
Equivalent resistance in a parallel combination is less than their individual value.
AG = BG equation must be true
Answer:
solution
we know that .
s=ut+½at²
now, putting the values in the second equation of motion ,
we get,
S=20×10+1/2×(10)²
S=200+1×100
S=200+100
S=300m
the distance covered by given body or object in 10 seconds is 300 m.