A cyclist intends to cycle up a 7.70o hill whose vertical height is 126m. Assuming the mass of bicycle plus person is 75.0kg, ca
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Answer:
The average induced emf around the border of the circular region is .
Explanation:
Given that,
Radius of circular region, r = 1.5 mm
Initial magnetic field, B = 0
Final magnetic field, B' = 1.5 T
The magnetic field is pointing upward when viewed from above, perpendicular to the circular plane in a time of 125 ms. We need to find the average induced emf around the border of the circular region. It is given by the rate of change of magnetic flux as :
So, the average induced emf around the border of the circular region is .
Answer:
757,93 feets
Explanation:
We can make a right triangle between the boat (A), the Coast Guard officer (B) and the base of the observation tower (C), like in the graph attached. Now, you could also made a rectangle, adding the horizontal at the height of the Coast Guard, starting in B and ending in D, the vertex opossing C.
The angle of depression, its O in the graph.
Now, as we got an rectangle, of course, the segment AD its the same length as CB, and CA, the distance from the boat to shoreline, its the same length as DB.
ADB its an right triangle, with AB, the hypothenuse, and BD and DA, the catheti (or <em>legs</em>).
Now, we know the lenght BC, the height of the tower, 53 feets, so we also know the lenght of DA. DA its the opposite cathetus to the angle O. We wish to know the length AC, equal to the lenght DB, the adjacent cathetus of the angle O.
Know, the trigonometric function that connects the adjacent cathetus with the opossite cathetus its the tangent.
We can take that the angle O = 4 °, and knowing that the opossite cathetus its 53 feets, we got:
This its equal to the distance from the boat to the shoreline.
