Answer: The question has some details missing. here is the complete question ; Point charge 1.5 μC is located at x = 0, y = 0.30 m, point charge -1.5 μC is located at x = 0 y = -0.30m. What are (a)the magnitude and (b)direction of the total electric force that these charges exert on a third point charge Q = 5.0 μC at x = 0.40 m, y = 0
Explanation:
- a) First of all find the distance between the two charges;
- x = 0, y = 0.30 and x = 0.40 m, y = 0
hence, the force F = 2Kq1q2cosθ /r²...............equation 1
but cosθ = y/r = 0.3/0.5
cosθ = 0.6
plugging back to equation 1;
F = 2 x 9 x 10^9 x 1.5 x 10^-6 x 5 x 10^-6 /0.5^2
F = 540 x 10^-3
Magnitude of Force = 0.54N
b) Direction is at angle 90
Answer:
impulse acting on it
Explanation:
The impulse is defined as the product between the force applied to an object (F) and the time interval during which the force is applied (
):
We can prove that this is equal to the change in momentum of the object. In fact, change in momentum is given by:
where m is the mass and 
is the change in velocity. Multiplying and dividing by , we get
and since 
is equal to the acceleration, a, we have
And since the product (ma) is equal to the force, we have
which corresponds to the impulse.
The thing that happens to the speed of the pulse when you stretch the hose more tightly is that it increases.
<h3>What is wage speed?</h3>
It should be noted that wave speed simply means the distance that a wave travels during a particular time.
It should be noted that higher tension leads to an increase in the speed of the wave.
Therefore, the thing that happens to the speed of the pulse when you stretch the hose more tightly is that it increases.
Learn more about speed on:
brainly.com/question/13943409
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Answer:
1340.2MW
Explanation:
Hi!
To solve this problem follow the steps below!
1 finds the maximum maximum power, using the hydraulic power equation which is the product of the flow rate by height by the specific weight of fluid
W=αhQ
α=specific weight for water =9.81KN/m^3
h=height=220m
Q=flow=690m^3/s
W=(690)(220)(9.81)=1489158Kw=1489.16MW
2. Taking into account that the generator has a 90% efficiency, Find the real power by multiplying the ideal power by the efficiency of the electric generator
Wr=(0.9)(1489.16MW)=1340.2MW
the maximum possible electric power output is 1340.2MW
T= 3.34
Vi= 0
A= 9.81
D= ?
d=Vit+1/2at^2
d= 1/2(9.81)(3.34)2
d= 54.7 or 55 meters tall
