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Karolina [17]
3 years ago
13

Your own car has a mass of 2000 kg. If your car produces a force of 5000 N, how fast will it accelerate?

Physics
1 answer:
Sidana [21]3 years ago
7 0

Answer:

2.5m/s²

Explanation:

Given parameters:

Mass of car  = 2000kg

Force produced by the car  = 5000N

Unknown:

Acceleration of the car  = ?

Solution:

According to Newton's second law of motion, Force is a product of mass and acceleration.

  Force  = mass x acceleration

Now, insert the parameters and find the unknown;

  5000 = 2000 x acceleration

   Acceleration  = \frac{5000}{2000}   = 2.5m/s²

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vA 61.2-kg circus performer is fired from a cannon that is elevated at an angle of 57.8 ° above the horizontal. The cannon uses
dsp73

Answer:

The effective spring constant of the firing mechanism is 1808N/m.

Explanation:

First, we can use kinematics to obtain the initial velocity of the performer. Since we know the angle at which he was launched, the horizontal distance and the time in which it's traveled, we can calculate the speed by:

v_0_x=\frac{x}{t}\\ \\v_0\cos\theta=\frac{x}{t}\\\\v_0=\frac{x}{t\cos\theta}

(This is correct because the horizontal motion has acceleration zero). Then:

v_0=\frac{20.8m}{(2.60s)\cos57.8\°}\\\\v_0=15.0m/s

Now, we can use energy to obtain the spring constant of the firing mechanism. By the conservation of mechanical energy, considering the instant in which the elastic band is at its maximum stretch as t=0, and the instant in which the performer flies free of the bands as final time, we have:

E_0=E_f\\\\U_e=K\\\\\frac{1}{2}kx^2=\frac{1}{2}mv^2\\\\\implies k=\frac{mv^2}{x^2}

Then, plugging in the given values, we obtain:

k=\frac{(61.2kg)(15.0m/s)^2}{(2.76m)^2}\\\\k=1808N/m

Finally, the effective spring constant of the firing mechanism is 1808N/m.

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A spinning top is the answer
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