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Sliva [168]
3 years ago
12

A hot air balloon is traveling vertically upward at a constant speed of 2.8 m/s. When

Physics
2 answers:
PtichkaEL [24]3 years ago
8 0
We can use the equation of motion: 
2as = v² - u²; where s = 29 m, a = 9.8 m/s², u = -2.8 m/s
v = √(2 x 29 x 9.8 + 2.8²)
v = 24. 0 m/s 
swat323 years ago
6 0
<span>why is your formula x=? if i'm reading it right the formula is the height of the object at time t. That being the case, set your setup (which looks right) equal to 0 and solve for t. This will tell you how long it takes to hit the ground. Plug this value of t into the forumla -9.8t+2.8 and that will tell you the speed at time t.</span>
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Can any one please help
Alenkasestr [34]

Answer:

20meters per second

Explanation:

2000meters/50seconds= 20m/s

8 0
3 years ago
an airplane accelerates down a runway at 3.20m/s2 for 32.8s until it finally lifts off the ground. Determine the distance travel
Butoxors [25]

from rest

dist = 1/2 accn timextime

=1/2 3.2 32.8x32.8

about 1.6x900 m/s ... 1350m

6 0
3 years ago
Find a) molar fraction, b) concentration in mol / and c) concentration in mol / kg of an aqueous solution with 25% alcohol: the
igor_vitrenko [27]

Explanation:

Answer

( 58.3 mL ) (

0.789 g

1 mL

) (

1 mole

46 g

) = 1 mole C2H5OH

( 500 mL H2O ) (

1 g

1 mL

) (

1 mole

18 g

) = 27.8 mole H2O

The total moles = 1 mole C2H5OH + 27.8 mole H2O = 28.8 moles

The mole fraction =

moles C2H5OH

total moles

=

1 mole C2H5OH

28.8 total moles

= 0.035

The mole percent would be 3.5%.

What is the weight fraction?

Answer

( 58.3 mL ) (

0.789 g

1 mL

) = 46 g C2H5OH

( 500 mL H2O ) (

1 g

1 mL

) = 500 g H2O

The total mass = 46 g C2H5OH + 500 g H2O = 546 g

The mass fraction =

mass C2H5OH

total mass

=

46 g C2H5OH

546 total grams

= 0.084

The mass percent would be 8.4%.

What is the molarity?

Answer

The molarity =

moles C2H5OH

L of solution

=

1 mole C2H5OH

.5583 L

= 1.79 M

What is the molality?

Answer

The molality =

moles C2H5OH

kg of solvent

=

1 mole C2H5OH

0.5 kg H2O

= 2

8 0
3 years ago
1 point
s2008m [1.1K]

Answer:

The person has no displacement

Explanation:

The given parameters are

The location of the person = The equator

The distance covered in one revolution = Total distance around the body

The total distance around the Earth = The circumference of the Earth = 40.075 kilometres

The total distance moved by the person standing at the equator during the Earths complete revolution = 40,075 kilometres

The initial location of the person in relation to a fixed point in space outside Earth at the start of the revolution = x km

The final location of the person in relation to the fixed point in space outside Earth at the completion of the revolution = x km

The displacement = Change in position = Final location - Initial location  

∴ The displacement = x km - x km = 0 km.

5 0
4 years ago
Can anyone help me in this question?
Anna71 [15]

Answer:

I guess the answer is charging by friction

3 0
3 years ago
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