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3 years ago

How is the force of gravity mathematically related to the factors that answer Question I?

Physics

1 answer:

Vadim26 [7]3 years ago

3 0

Answer:

Probably the more correct version of the story is that Newton, upon observing an apple fall from a tree, began to think along the following lines: The apple is accelerated, since its velocity changes from zero as it is hanging on the tree and moves toward the ground. Thus, by Newton's 2nd Law there must be a force that acts on the apple to cause this acceleration. Let's call this force "gravity", and the associated acceleration the "acceleration due to gravity". Then imagine the apple tree is twice as high. Again, we expect the apple to be accelerated toward the ground, so this suggests that this force that we call gravity reaches to the top of the tallest apple tree.

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A spherical submersible 1.84 m in radius, armed with multiple cameras, descends under water in a region of the Atlantic Ocean kn

Drupady [299]

Answer:

23932242.5 Pa

Explanation:

$P_a$ = Atmospheric pressure = $1.013\times 10^5\ Pa$

$P_w$ = Pressure of seawater

$\rho$ = Density of sea water = $1.025\times 10^3\ kg/m^3$

h = Depth of shipwreck = $2.37\times 10^3\ m$

g = Acceleration due to gravity = 9.81 m/s²

The absolute pressure is given by

$P_{ab}=P_a+P_w\\\Rightarrow P_{ab}=1.013\times 10^5+1.025\times 10^3\times 9.81\times 2.37\times 10^3\\\Rightarrow P_{ab}=23932242.5\ Pa$

The absolute pressure at the depth of the shipwreck is 23932242.5 Pa

5 0

3 years ago

A 75.00 gram sample of an unknown metal initially at 99.0 degrees Celcius is added to 50.00 grams of water initially at 10.79 de

jeyben [28]

Answer:

$c_{e1}$ = 0.331 J / g ° C

Explanation:

We have a calorimetry exercise where all the heat yielded by one of the components is absorbed by the other.

Heat ceded Qh = m1 ce1 ( $T_{h}$ - $T_{f}$ )

Heat absorbed Qc = m2 ce2 ( $T_{f}$ - T₀)

Body 1 is metal and body 2 is water . Where m are the masses of the two bodies, ce their specific heat and T the temperatures

Qh = Qc

m₁ $c_{e1}$ ( $T_{h}$ - $T_{f}$ ) = m₂ $c_{e2}$ ( $T_{f}$ - T₀)

we clear the specific heat of the metal

$c_{e1}$ = m₂ $c_{e2}$ ( $T_{f}$ - T₀) / (m₁ ( $T_{h}$ - $T_{f}$ ))

$c_{e1}$ = 50.00 4.184 (20.15 -10.79) / (75.00 (99.0-20.15))

$c_{e1}$ = 209.2 (9.36) / (75 78.85)

$c_{e1}$ = 1958.11 / 5913.75

$c_{e1}$ = 0.331 J / g ° C

5 0

4 years ago

What can you conclude about the direction of motion of the object after the application of the additional force?

Anna35 [415]

It will move in the direction of applied force following the law of newton that is an object is stationary until an external force is applied then it moves in direction of force

5 0

3 years ago

PLS HELP!!! Response: Develop a unique example (not posted on the discussion board by anyone else) and calculate the resultant d

Jlenok [28]

Answer:

he is the first person can be 3in and a 6man is the best not a man of the hartford

8 0

3 years ago

1) An ac source of period T and maximum voltage V is connected to a single unknown ideal element that is either a resistor, and

Lady_Fox [76]

Answer: Capacitor

Explanation:

Given the following ;

At time, t = T/4 ; I = 0

At time, t = T/2 ; I = - Imax

Where T = period

We can confirm what the unknown element is by using the relation, such that the parameters satisfy the stated condition ;

Recall;

I = Iosin(wt + π/2) [for CAPACITOR]

w = 2π/T

At t = T/4

I = Iosin(2π/T(T/4) + π/2)

I = Iosin(π/2 + π/2)

I = Iosin(0)

I = 0

At t = T/2

I = Iosin(2π/T(T/2) + π/2)

I = Iosin(π + π/2)

I = Iosin(0)

I = Iosin(3π/2)

I = Iosin(540/2)

I = Iosin(270)

I = -Io

Note : Io = Imax

Both conditions are met, Hence, the unknown element is a CAPACITOR.

6 0

3 years ago