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just olya [345]
4 years ago
8

An element has two naturally occurring isotopes, X-85 with a mass of 84.9118 amu and a natural abundance of 72.17%, and X-87 wit

h a mass of 86.9092 amu and a natural abundance of 27.83%. Calculate the atomic mass of this element.
Chemistry
1 answer:
QveST [7]4 years ago
5 0

Answer:

This element is Rubidium (Rb) and has an average atomic mass of 85.468 u

Explanation:

The average mass of an element is calculated by taking the average of the atomic masses of its stable isotopes.

The enitre atomic mass = 100 % or 1

⇒ this consists of X-85 with 72.17 % abundance  with atomic massof  84.9118 g/mol

72.17 % = 0.7217

⇒ this consists of X-87 with  27.83 % abundance with atomic mass of 86.9092 g/mol

27.83 % = 0.2783

To calculate the mass of this isotope we use the following:

0.7271 * 84.9118 + 0.2783 * 86.9092 =85.468 g/mol

This element is Rubidium(Rb) and has an average atomic mass of 85.468 u

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Using your knowledge of thermochemistry, what equation is appropriate to calculate the heat produced from the HCl-NaOH reaction?
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Answer:

Neutralization equation:

HCl + NaOH  → NaCl + H₂O + Heat

Heat would calculated through,

Q = m . c. ΔT

Explanation:

When aqueous sodium hydroxide and hydrochloric acid react with each other a neutralization reaction occur. It produces water and salt. The salt would be sodium chloride.

Chemical equation:

HCl + NaOH  → NaCl + H₂O + Heat

The heat produces can be calculated through the given formula.

Q = m . c. ΔT

Q = amount of heat produces

m = total mass of solution

ΔT = change in temperature of solution

C = specific heat capacity of solution

As the mostly solutions are water so we take the specific heat capacity of water which is 4.186 j/g .°C

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Which of these statements best describes the formula unit for a compound made from Mg and Cl?
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It is MgCl₂ because the total positive charge on Mg is two

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The bond between the atoms that makes up the formula unit of the compound is an ionic bond. This bond involves the transfer of electrons between atoms.

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If 83.6 grams of H2 and 257 grams of N2 react, how many grams of ammonia will be produced?
SSSSS [86.1K]

The mass of ammonia that would be produced is 312.5 g

First, we will write a balanced chemical equation for the reaction

The balanced chemical equation for the reaction is

3H₂(g) + N₂(g) → 2NH₃(g)

This means

3 moles of hydrogen gas reacts with 1 mole of nitrogen gas to produce 2 moles of ammonia.

First, we will determine the number of moles of each reactant present

For Hydrogen (H₂)

Mass = 83.6 g

Molar mass = 2.016 g/mol

Using the formula

Number\ of\ moles = \frac{Mass}{Molar\ mass}

Number of moles of H₂ present = \frac{83.6}{2.016}

∴ Number of moles of H₂ present = 41.468254 moles

For Nitrogen (N₂)

Mass = 257 grams

Molar mass = 28.0134 g/mol

∴ Number of moles of N₂ present = \frac{257}{28.0134}

Number of moles of N₂ present = 9.174181 moles

Since,

3 moles of hydrogen gas reacts with 1 mole of nitrogen gas to produce 2 moles of ammonia

Then,

27.522543 moles of hydrogen gas will react with the 9.174181 moles of nitrogen gas to produce 18.348362 moles of ammonia

∴ 18.348362 moles of ammonia will be produced during the reaction

Now, for the mass of ammonia that would be produced

From the formula

Mass = Number of moles × Molar mass

Molar mass of ammonia = 17.031 g/mol

Mass of ammonia that would be produced = 18.348362 × 17.031

Mass of ammonia that would be produced = 312.49095 g

Mass of ammonia that would be produced ≅ 312.5 g

Hence, the mass of ammonia that would be produced is 312.5 g

Learn more here: brainly.com/question/13902065

3 0
3 years ago
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