Answer:
Decarboxylation is a chemical reaction that removes a carboxyl group and releases carbon dioxide (CO2). Usually, decarboxylation refers to a reaction of carboxylic acids, removing a carbon atom from a carbon chain.
Explanation:
Please give me brainlist
Answer:
1. NaN₃(s) → Na(s) + 1.5 N₂(g)
2. 79.3g
Explanation:
<em>1. Write a balanced chemical equation, including physical state symbols, for the decomposition of solid sodium azide (NaN₃) into solid sodium and gaseous dinitrogen.</em>
NaN₃(s) → Na(s) + 1.5 N₂(g)
<em>2. Suppose 43.0L of dinitrogen gas are produced by this reaction, at a temperature of 13.0°C and pressure of exactly 1atm. Calculate the mass of sodium azide that must have reacted. Round your answer to 3 significant digits.</em>
First, we have to calculate the moles of N₂ from the ideal gas equation.

The moles of NaN₃ are:

The molar mass of NaN₃ is 65.01 g/mol. The mass of NaN₃ is:

Answer:
When you place the north pole of one magnet near the south pole of another magnet, they are attracted to one another.
Explanation:
Answer: The beginning stage you decide to depict the area, or position, of an object.
Explanation: starting point or position
Answer: 19.71 feet
Explanation:
Given: Speed of Charlotte =58.6 mi/h
Since 1 hour = 3600 seconds
and 1 mile = 5280 feet
So, Speed of Charlotte =
mi/ sec
She looks down at her phone and takes her eyes off the road for 4.36 s.
Since , Distance = 
So, Distance = 
Hence, Charlotte traveled 19.71 feet during this time.