Answer:
1. RbOH(s) ⇒ Rb⁺(aq) + OH⁻(aq)
2. Na₂CO₃(s) ⇒ 2 Na⁺(aq) + CO₃²⁻(aq)
3. (NH₄)₂SeO₃(s) ⇒2 NH₄⁺(aq) + SeO₃²⁻(aq)
Explanation:
Let's consider the dissolving equations for the following compounds.
1. Rubidium hydroxide
RbOH(s) ⇒ Rb⁺(aq) + OH⁻(aq)
2. Sodium carbonate
Na₂CO₃(s) ⇒ 2 Na⁺(aq) + CO₃²⁻(aq)
3. Ammonium selenite
(NH₄)₂SeO₃(s) ⇒2 NH₄⁺(aq) + SeO₃²⁻(aq)
It is not a really good flammable object to use for fires.
And it doesn't let the fire have oxygen therefore the fire will go out<span />
Answer:
A) 5 sig figs
B) 4 sig figs
C) 4 sig figs
D) 4 sig figs
E) 5 sig figs
F) 3 sig figs
G) 5 sig figs
Explanation:
work for G- 1.250 x 105= 131.25
The answer is 2.53e-5, I unfortunately don't know how you would really show the work other than showing the division.
