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jarptica [38.1K]
4 years ago
11

Which flask has the solution with the lowest freezing point

Chemistry
1 answer:
scZoUnD [109]4 years ago
8 0

Answer:

Here's what I get  

Explanation:

Assume you have 0. 1 mol·kg⁻¹ solutions of A) KCl, B) CH₃OH, C) Ba(OH)₂, and D) CH₃COOH.

The formula for freezing point depression is

\Delta T_{f} = iK_{f}b

Where

  b = the molal concentration

K_f = the freezing point depression constant

    i = the van't Hoff i factor

The i-factor is the number of solute particles produced by one formula unit of the substance.

The only difference in the solutions is the i-factor of the solutes.

A) KCl

KCl(aq) ⟶ K⁺(aq) +Cl⁻(aq); i = 2

B) CH₃OH

Methanol is a nonelectrolyte.

CH₃OH(aq) ⟶ CH₃OH(aq); i = 1

C) Ba(OH)₂

Ba(OH)₂(aq) ⟶ Ba²⁺(aq) + 2OH⁻(aq); i = 3

D) CH₃COOH

CH₃COOH(aq) ⇌ CH₃COO⁻(aq)+ H⁺(aq); i ⪆ 1

The Ba(OH)₂ solution has the greatest i-value. It therefore has the greatest freezing point depression and the lowest freezing point.

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Explanation:

The color change is an indicator of a chemical reaction that has occurred. Although color changes are not necessarily good diagnostic tool to measure if a chemical reaction has occurred or not.

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Explain whether each of the possible reactions listed below will occur. For those that will, predict what the products will be.
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Answer:

Zn(s) + 2H₂O (l) → Zn(OH)2(aq) + H2(g)

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Explanation:

Metals reacts with liquid water to yield the corresponding metallic hydroxide and hydrogen gas as shown above; Zn(s) + 2H₂O (l) → Zn(OH)2(aq) + H2(g)

Tin reacts with oxygen to yield tin (IV) oxide. This is an oxidation reaction as shown; Sn(s) + O2(g) →SnO2(s)

The reaction between Cd and Pb(NO3)2 is a single replacement reaction. It is possible because Cd is above Pb in the electrochemical series. Hence the reaction occurs thus; Cd(s) + Pb(NO3)2 (aq) →Cd(NO3)2 (aq) + Pb(s)

Copper does not displace hydrogen from dilute acids (such as HCl) since copper is lower than hydrogen in the electrochemical series hence the reaction does  not occur.

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Explanation:

In this question, we can start with the <u>reaction mechanism</u> for the synthesis of Nerolin. We have to start with naphthalen-2-ol adding NaOH we can produce the alkoxide. Then this alkoxide can react by an <u>Sn2 reaction</u> with bromomethane to produce Nerolin (see figure 1).

In the starting molecule (naphthalen-2-ol) we have an <u>"OH" group</u>. Therefore we will have an <u>O-H stretch signal</u> around 3300 cm^-1. The alcohol signals are very broad and very intense, so this will be the main signal for the initial molecule. In the final product, we dont have the "OH" therefore this signal will disappear (see figure 2).

I hope it helps!

7 0
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