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jarptica [38.1K]
3 years ago
11

Which flask has the solution with the lowest freezing point

Chemistry
1 answer:
scZoUnD [109]3 years ago
8 0

Answer:

Here's what I get  

Explanation:

Assume you have 0. 1 mol·kg⁻¹ solutions of A) KCl, B) CH₃OH, C) Ba(OH)₂, and D) CH₃COOH.

The formula for freezing point depression is

\Delta T_{f} = iK_{f}b

Where

  b = the molal concentration

K_f = the freezing point depression constant

    i = the van't Hoff i factor

The i-factor is the number of solute particles produced by one formula unit of the substance.

The only difference in the solutions is the i-factor of the solutes.

A) KCl

KCl(aq) ⟶ K⁺(aq) +Cl⁻(aq); i = 2

B) CH₃OH

Methanol is a nonelectrolyte.

CH₃OH(aq) ⟶ CH₃OH(aq); i = 1

C) Ba(OH)₂

Ba(OH)₂(aq) ⟶ Ba²⁺(aq) + 2OH⁻(aq); i = 3

D) CH₃COOH

CH₃COOH(aq) ⇌ CH₃COO⁻(aq)+ H⁺(aq); i ⪆ 1

The Ba(OH)₂ solution has the greatest i-value. It therefore has the greatest freezing point depression and the lowest freezing point.

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what volume of co2 is produced at stp when 270g of glucose are consumed in the following reaction? c6h12o6 + 6o2(g) -> 6co2 (
lana [24]

Answer:

202 L

Explanation:

Step 1: Write the balanced equation

C₆H₁₂O₆ + 6 O₂(g) ⇒ 6 CO₂(g) + 6 H₂O(l)

Step 2: Calculate the moles corresponding to 270 g of C₆H₁₂O₆

The molar mass of C₆H₁₂O₆ is 180.16 g/mol.

270 g × 1 mol/180.16 g = 1.50 mol

Step 3: Calculate the moles of CO₂ generated from 1.50 moles of glucose

The molar ratio of C₆H₁₂O₆ to CO₂ is 1:6. The moles of CO₂ formed are 6/1 × 1.50 mol = 9.00 mol

Step 4: Calculate the volume of 9.00 moles of CO₂ at STP

The volume of 1 mole of an ideal gas at STP is 22.4 L.

9.00 mol × 22.4 L/mol = 202 L

4 0
3 years ago
How many grams of KCI can be dissolved in 63.5. g of water at 80
Masteriza [31]

Answer:

35.8 g

Explanation:

Step 1: Given data

Mass of water: 63.5 g

Step 2: Calculate how many grams of KCl can be dissolved in 63.5. g of water at 80 °C

Solubility is the maximum amount of solute that can be dissolved in 100 g of solute at a specified temperature. The solubility of KCl at 80 °C is 56.3 g%g, that is, we can dissolve up to 56.3 g of KCl in 100 g of water.

63.5 g Water × 56.3 g KCl/100 g Water = 35.8 g KCl

8 0
3 years ago
Which must be the same when comparing 1 mol of oxygen, O2, with 1 mol of carbon monoxide has, CO?
Sloan [31]
Answer: 1 mol of oxygen, O₂, and 1 mol of CO will have the same number of molecules, and the same number of atoms.

Justification:


Althought the question is too open, other answers may arise, the most remarkable similarity between the two compounds is that both are diatomic.

That means that both molecules oxygen, O₂, and carbon monoxide, CO have two atoms.

So, 1 mol of oxygen, O₂, and 1 mol of CO will have the same number of molecules, and the same number of atoms.


You must remember that 1 mol means a specific number. It is Avogadro's number, which is 6.022 × 10 ²³.

So 1 mol of CO and 1 mol of O₂ are the same number of representative particles: 6.022 ×10²³ molecules eac, and two times that number of atoms each (since each molecule has two atoms).
3 0
3 years ago
12g of carbon react with 32g of oxygen to produce 44g of CO2 .which chemical law do the data illustrate​
Julli [10]

Answer:

Law of constant composition

6 0
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