I’m assuming ‘dives further’ means to go directly down
the angle of elevation of the ship from the submarine is equal to the angle of depression of the submarine from the ship, if we assume the sea level is perpendicular to ‘directly down’.
let both of these angles to be = $ when the submarine is at A and ¥ when the submarine is at B (excuse the lack of easily accessible variables as keys)
then this become a simple trig problem:
A)
Let O be the position of of the ship, and C be the original position of the submarine.
therefore, not considering direction
|OC| = 1.78km = 1780m
|CA| = 45m
these are the adjacent and opposite sides of a right angled triangle.
But tan($) = opp/adj = |CA|/|OC| = 45/1780
therefore $ = arctan(45/1780) which is roughly 1.45 degrees,
B)
similarly, noting that |CB| = |CA| + |AB| = 45 + 62 = 107m
tan(¥) = 107/1780
¥ = arctan(107/1780) which is roughly 3.44 degrees
Answer:
The domain of the function is R i.e. any real value.
Step-by-step explanation:
The given figure is a graph on the coordinate plane of the function 
Now, the domain of a function means that the values of x (Independent variable) for which the function is valid i.e. the y values are real.
It is clear from the equation given above that for any real value of x there will be a real corresponding value of y.
Therefore, the domain of the function is R i.e. any real value. (Answer)
Answer:
567 i think
Step-by-step explanation:
