Answer:
2000 years
Explanation:
A radioactive molecule will continuously decay and turn into another molecule. This nature of the radioactive molecule makes them can be used to estimate the age of an object. Half-life is the unit of time needed for radioactive molecules to decay to half of its mass. The formula for the mass remaining will be:
Where
N(t)= number of the molecule remains
N0= number of molecule initially
t= time elapsed
t1/2= half time
We have all variable besides the half time, the calculation will be:
3= 6000/ (t1/2)
t1/2= 6000/3= 2000
The half-life is 2000 years
Answer:
The answer to your question is 2.92 x 10⁻⁶ g
Explanation:
Data
mass of K = ?
atoms of K = 4.50 x 10¹⁶
Process
To answer this question just remember that the atomic mass of any element is equivalent to Avogadro's number.
1.- Look for the atomic number of Potassium
Atomic number = 39.10 g
2.- Use proportions and cross multiplication
39.10 g of K --------------- 6.023 x 10²³ atoms
x ----------------4.50 x 10¹⁶ atoms
x = (4.50 x 10¹⁶ x 39.10) / 6.023 x 10²³
-Simplify
x = 1.7595 x 10¹⁸ / 6.023 x 10²³
-Result
x = 2.92 x 10⁻⁶ g
Aluminum reacts with hydrochloric acid to produce aluminum chloride and hydrogen gas. 2 al(s) + 6 hcl(aq) → 2 alcl3(aq) + 3 h2(g) what mass of h2(g) is produced from the reaction of 1.35 g al(s) with excess hydrochloric acid?
Answer:
5118.50 J
Explanation:
pΔv=nRΔT ;
therefore, ΔT=PV/nR
ΔT = (6.4×10^5)(3.2×10^(-3)/1×8.314
ΔT= 2.4633×10^2 = 246.33 K
specific heat at constant pressure is given as:
c_p = 3/2R
c_p = 12.5 J/mol K
Now, substitute in equation (1)
we know that
Q=ΔU+W ;
and
W=pΔV= 6.4×10^5×3.2×10^(-3) = 2048 J
now
ΔU=CvΔT = 12.465×246.33 =3070.50 J ;
therefore
Q=3070.50+2048= 5118.50 J
Answer:
The inner core
Explanation:
Well, Jaron's tunneling machine would find it quite impossible to even penetrate the crust.
Our dynamic earth is arranged in concentric layers with each shell at varrying physical state and chemical properties.
As we go down the earth, the temperature and pressure increases significantly. The innermost layer of the erth is the inner core and it is expected that the temperature and pressure here should be the greatest. The pressure in the inner core is so great that the materials that were supposed to be in molten form exists as solid in there.
