Moles = Molarity x Volume
Moles = 2.0 x 0.50
= 1.0 mole
hope this helps!
swift to hear, slow to speak
Explanation:
<em><u>look at the clues by it and try not to trust the links they trying to give u...</u></em>
<em><u>but i kinda dont know myself any periodic table i can look at?</u></em>
Answer:
6,216.684 kilograms of sodium carbonate must be added to neutralize
of sulfuric acid solution.
Explanation:
Mass of sulfuric acid solution = ![6.05\times 10^3 kg=6.05\times 10^6 g](https://tex.z-dn.net/?f=6.05%5Ctimes%2010%5E3%20kg%3D6.05%5Ctimes%2010%5E6%20g)
![1 kg = 10^3 g](https://tex.z-dn.net/?f=1%20kg%20%3D%2010%5E3%20g)
Percentage mass of sulfuric acid = 95.0%
Mass of sulfuric acid = ![\frac{95.0}{100}\times 6.05\times 10^6 g](https://tex.z-dn.net/?f=%5Cfrac%7B95.0%7D%7B100%7D%5Ctimes%206.05%5Ctimes%2010%5E6%20g)
![=5,747,500 g](https://tex.z-dn.net/?f=%3D5%2C747%2C500%20g)
Moles of sulfuric acid = ![\frac{5,747,500 g}{98 g/mol}=58,647.96 mol](https://tex.z-dn.net/?f=%5Cfrac%7B5%2C747%2C500%20g%7D%7B98%20g%2Fmol%7D%3D58%2C647.96%20mol)
![H_2SO_4+Na_2CO_3\rightarrow Na_2SO_4+CO_2+H_2O](https://tex.z-dn.net/?f=H_2SO_4%2BNa_2CO_3%5Crightarrow%20Na_2SO_4%2BCO_2%2BH_2O)
According to reaction , 1 mole of sulfuric acid is neutralized by 1 mole of sodium carbonate.
Then 58,647.96 moles of sulfuric acisd will be neutralized by :
of sodium carbonate
Mass of 58,647.96 moles of sodium carbonate :
![106 g/mol\times 58,647.96 mol=6,216,683.76 g](https://tex.z-dn.net/?f=106%20g%2Fmol%5Ctimes%2058%2C647.96%20mol%3D6%2C216%2C683.76%20g)
6,216,683.76 g = 6,216,683.76 × 0.001 kg = 6,216.684 kg
6,216.684 kilograms of sodium carbonate must be added to neutralize
of sulfuric acid solution.