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poizon [28]
3 years ago
6

The decomposition of nitrogen dioxide is described by the following chemical equation:

Chemistry
1 answer:
kow [346]3 years ago
3 0

Answer:

The balanced chemical equation will be "NO_{2}+O\rightarrow NO+O_{2}".

Explanation:

The given equation is:

2NO_{2}\rightarrow 2NO+O_{2}

<u>Step 1:</u>

<u></u>2NO_{2}\rightarrow NO+O...(equation 1)

<u>Step 2:</u>

<u></u>NO_{2}+O\rightarrow NO+O_{2}...(equation 2)

On adding "equation 1" and "equation 2", we get

⇒  NO_{2}+NO_{2}+O\rightarrow NO+O+NO+O_{2}

⇒  2NO_{2}\rightarrow 2NO+O_{2}

The second step:

⇒  NO_{2}+O\rightarrow NO+O_{2}

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Answer:

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Explanation:

Hello,

In this case, we can solve this problem by noticing that the heat lost by the warm water is gained by the ice in order to melt it:

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In such a way, the cooling of water corresponds to specific heat and the melting of ice to sensible heat and specific heat also that could be represented as follows:

m_{water}Cp_{water}(T_2-T_{water})=-m_{ice}\Delta H_{melting,ice}-m_{ice}\Cp_{ice}(T_2-T_{ice})

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m_{water}Cp_{water}(T_2-T_{water})+m_{ice}Cp_{ice}(T_2-T_{ice})=-m_{ice}\Delta H_{melting,ice}\\\\T_2=\frac{-m_{ice}\Delta H_{melting,ice}+m_{water}Cp_{water}T_{water}+m_{ice}Cp_{ice}T_{ice}}{m_{water}Cp_{water}+m_{ice}Cp_{ice}} \\\\T_2=\frac{-50.0*334+100*4.18*67+50.0*2.04*-20.0}{100*4.18+50.0*2.04} \\\\T_2=17.8\°C

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