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3 years ago

• Why do some earthquakes cause more damage than others?

1 answer:

4 0

Because each fault line has different types of pressure being held, and some fault lines can hold more pressure before being released, resulting a larger eq, and some other lines hold less pressure resulting in a smaller eq... hope I was helpful :)

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An incident ray that passes through the vertex of a convex lens:

WINSTONCH [101]

The answer is refracts parallel to the axis of the lens

7 0

3 years ago

For a maximum superelevation of 0.08 ft/ft and a degree of curve of 4o, calculate the maximum safe speed for the curve assuming

Mamont248 [21]

Answer:

Explanation:

Given that

Superelation= 0.08ft/ft

Given curve= u•

Curve junction factor= 0.13

DR= 5729.57795

R = 5729.57795/D

R = 5729.57795/4

R = 1432.4ft

c + f = V^2/gG

0.08 + 0.13 = V^2 / (32*1432.4)

V^2 = 9625.728 or V = 98 ft/sec

The designed speed for a project considered is a minimum value which means the highway design elements will meet or exceed the standards for the design speed. The maximum safe speed under normal condition is significantly greater than design speed

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3 years ago

An object floats in water with 5 8 of its volume submerged. The ratio of the density of the object to that of water is

ki77a [65]

Answer:

$\dfrac{5}{8}$

Explanation:

m = Mass of object = $\rho v$

m' = Mass of water = $\rho' v'$

$\rho$ = Density of object

$\rho'$ = Density of water

Weight of the water displaced is the force in the case of floating objects

According to the question

$v'=\dfrac{5}{8}v$

In the case of floating objects

$W=W'\\\Rightarrow mg=m'g\\\Rightarrow \rho vg=\rho'v'g\\\Rightarrow \rho v=\rho' \dfrac{5}{8}vg\\\Rightarrow \rho=\rho' \dfrac{5}{8}\\\Rightarrow \dfrac{\rho}{\rho'}=\dfrac{5}{8}$

The ratio of the density of the object to that of water is $\dfrac{5}{8}$

3 0

3 years ago

If a mass of 76 kg acts downward 0.38 m from the axis of rotation on one end of a board and another force of 129 N also acts dow

Semenov [28]

Answer:

y = 2.196 m

Explanation:

Mass, m = 76 kg

distance from axis of rotation, x = 0.38 m

Second Force, F = 129 N

moment arm of the second force, y = ?

Now, equating moments for the equilibrium

So,

m g × x = F x y

76 x 0.38 x 9.81 = 129 x y

$y = \dfrac{76\times 0.38\times 9.81}{129}$

y = 2.196 m

Hence, the length of the moment arm is equal to 2.196 m.

6 0

3 years ago

Look at the circuit diagram. Which of these components is part of the circuit?

Roman55 [17]

Answer:

b ac power source

Explanation:

ieififuffucjcjcicogore8e8e9e9e9e9ew0ww0w0w

7 0

3 years ago