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Marrrta [24]
2 years ago
8

For a fixed amount of gas at a fixed temperature, what will happen if the volume is doubled?.

Physics
1 answer:
mash [69]2 years ago
4 0

Answer:

the pressure will decrease by 1/2

Explanation:

PV=nRT

P=(nRT)/(V)

nRT are all constant so they will equal 1

V is 2

P=1/2

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In lecture, it was discussed measurements of mass, temperature, time, volume and length. which of these is not an si base unit (
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From the options provided in the question, the measurement which is not an SI base unit is volume.

<h3>What is SI base unit?</h3>

This is referred to as the standard and fundamental unit of measurement of various quantities or variables which is defined arbitrarily and not by combinations of other units.

Volume is a quantity which is derived from the combination of lengths in a  three-dimensional manner which is why the formula is length× breadth×height and the unit is cm³. This is gotten from the combination of the unit of length which is cm.

This is therefore the reason why volume was chosen as the most appropriate choice.

Read more about Volume here brainly.com/question/463363

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1 year ago
A uniform disk has a moment of inertia that is (1/2)MR2. A uniform disk of mass 13 kg, thickness 0.3 m, and radius 0.2 m is loca
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The angular momentum of an object is equal to the product of its moment of inertia and angular velocity.
L = Iω
I = 1/2 MR²
I = 1/2 x 13 x (0.2)
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ω = 2π/0.3
ω = 20.9

L = 1.3 x 20.9
= 27.2 kgm²/s
6 0
3 years ago
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Your partner has been working on your group's circuit and has left the work area. before you begin working on the circuit, what
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The normal formula to find force is F = m* a. What kind of math do you need to do
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3 0
3 years ago
A rocket in deep space has an empty mass of 150 kg and exhausts the hot gases of burned fuel at 2500 m/s. It is loaded with 600
3241004551 [841]

Answer:

v(10\,s) \approx 775.387\,\frac{m}{s}

v(20\,s)\approx 1905.350\,\frac{m}{s}

v(30\,s) \approx 4023.595\,\frac{m}{s}

Explanation:

The speed of the rocket is given the Tsiolkovsky's differential equation, whose solution is:

v (t) = v_{o} - v_{ex}\cdot \ln \frac{m}{m_{o}}

Where:

v_{o} - Initial speed of the rocket, in m/s.

v_{ex} - Exhaust gas speed, in m/s.

m_{o} - Initial total mass of the rocket, in kg.

m - Current total mass of the rocket, in kg.

Let assume that fuel is burned linearly. So that,

m(t) = m_{o} + r\cdot t

The initial total mass of the rocket is:

m_{o} = 750\,kg

The fuel consumption rate is:

r = -\frac{600\,kg}{30\,s}

r = -20\,\frac{kg}{s}

The function for the current total mass of the rocket is:

m(t) = 750\,kg - (20\,\frac{kg}{s} )\cdot t

The speed function of the rocket is:

v(t) = - 2500\,\frac{m}{s}\cdot \ln \frac{750\,kg -(20\,\frac{kg}{s} )\cdot t}{750\,kg}

The speed of the rocket at given instants are:

v(10\,s) \approx 775.387\,\frac{m}{s}

v(20\,s)\approx 1905.350\,\frac{m}{s}

v(30\,s) \approx 4023.595\,\frac{m}{s}

7 0
3 years ago
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