(1) The time of motion of the arrow is 0.25 s.
(2) The vertical height dropped by the arrow as it approaches the target is 0.31 m.
The given parameters:
- <em>Horizontal distance of the arrow, X = 20 m</em>
- <em>Horizontal speed of the arrow, v = 80 m/s</em>
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The time of motion of the arrow is calculated as follows;
The vertical height dropped by the arrow as it approaches the target is calculated as follows;
Learn more about time of motion of projectile here: brainly.com/question/1912408
He should confront her about it and if after that point she continues report it to the chess team
Answer:
The answer to your question is given below.
Explanation:
From the diagram given in the question, we can see that the bulbs are in parallel connection. This implies that different current will go through the bulb but the same voltage. But the resistance of each bulb is the same, therefore the same current current will go through them.
This can further be understood if we determine the current flowing through each bulb. This is illustrated below:
Voltage (V) = 30V
Resistant 1 (R1) = 15Ω
Current 1 (I1) =..?
V = I1R1
30 = I1 x 15
Divide both side by 15
I1 = 30/15
I1 = 2A.
Voltage (V) = 30V
Resistant 2 (R2) = 15Ω
Current 2 (I2) =..?
V = I2R2
30 = I2 x 15
Divide both side by 15
I2 = 30/15
I2 = 2A.
The overall current(I) in the circuit:
I = I1 + I2
I = 2 + 2 = 4A.
From the illustrations above, we can see that the same current will flow through each bulb as the will current split into two equal parts
Answer:the source of a wave
Explanation:
