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3 years ago

6. Is an object moving in uniform circular motion accelerating? Explain.

Physics

1 answer:

n200080 [17]3 years ago

4 0

An object moving in a circle is accelerating. Accelerating objects are objects which are changing their velocity.

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Suppose the B string on a guitar is 24" long and vibrates with a frequency of about 247 Hz. You place your finger on the 5th fre

pashok25 [27]

To solve this problem it is necessary to apply the related concepts to string vibration. This concept shows the fundamental frequency of a string due to speed and length, that is,

$f = \frac{v}{2L}$

Where

v = Velocity

L = Length

Directly if the speed is maintained the frequency is inversely proportional to the Length:

$f \propto \frac{1}{L}$

Therefore the relationship between two frequencies can be described as

$\frac{f_2}{f_1}=\frac{l_1}{l_2}$

$f_2 = \frac{l_1}{l_2}(f_1)$

Our values are given as,

$l_1 = 24"\\f_1 = 247Hz\\l_2 = 18"$

Therefore the second frequency is

$f_2 = \frac{l_1}{l_2}(f_1)\\f_2 = \frac{24}{18}(247)\\f_2 = 329.33Hz$

The frequency allocation of 329Hz is note E.

8 0

3 years ago

What is Newton’s 3rd Law of Motion?

sasho [114]

Answer:

His third law states that for every action (force) in nature there is an equal and opposite reaction. In other words, if object A exerts a force on object B, then object B also exerts an equal and opposite force on object A. Notice that the forces are exerted on different objects.

Explanation:

5 0

3 years ago

The gravitational force of attraction between two objects would increase by

OleMash [197]

The gravitational force of attraction between two objects would be increased by "decreasing the distance between two objects"

Hope this helps!

6 0

3 years ago

A loaded ore car has a mass of 950 kg and rolls on rails with negligible friction. It starts from rest and is pulled up a mine s

Ierofanga [76]

Answer:

a). P=11.04kW

b). Pmax=11.38 kW

c). Wt=6423.166kJ

Explanation:

The power of the motor when the speed is constant is the work in a determinate time.

$P=\frac{W}{t}$

The work is the force the is applicated in a distance so

W=F*d

replacing:

$P=F*\frac{d}{t}$ and $\frac{d}{t}$ determinate distance in time is velocity so

a).

$P=F*v$

$F=m*a\\F=m*g*sin(33.5)$

$P=950kg*9.8\frac{m}{s^{2}}*sin(33.5)*2.15\frac{m}{s}\\P=11047.846 W\\P=11.0478 kW$

b).

The maximum power must the motor provide, is the maximum force with the maximum speed of the motor in this case

The first step is find the acceleration so

$vi=0\frac{m}{s} \\vf=2.15 \frac{m}{s}\\vf=vi+a*t\\vf-vi=a*t\\ a=\frac{vf-vi}{t}= a=\frac{2.15\frac{m}{s}-0\frac{m}{s}}{13s}\\a=0.1653 \frac{m}{s^{2}}$

The maximum force is when the car is accelerating so

$Ft=Fa+Fg\\Ft=m*a+m*g*sin(33.5)\\Ft=950kg*0.1653\frac{m}{s^{2}}+950*9.8\frac{m}{s^{2}}*sin(33.5)\\Ft=5295.565 N$

so the maximum force is the maximum force by the maximum speed

$Pmax=Ft*v\\Pmax=5295.565N*2.15\frac{m}{s}\\Pmax=11385.46\\Pmax=11.3854kW$

c).

The total energy transfer without any friction is the weight move in the high axis y in this case, so is easy to know that distance

W=m*g*h

h=Length*sin(33.5)

W=m*g*Length*sin(33.5)

W=950 kg*9.8* 1250m*sin(33.5)

W=6423166.667 kJ

W=6423.166 kJ

4 0

4 years ago

A ball is thrown straight upward. How does the sign of the work done by gravity while the ball is traveling upward compare with

Vlada [557]

If I’m understanding this. Th reason why the ball can resist gravity’s pull is because the force used to throw it up was greater than gravity’s pull on it. BTW, gravity’s pull is 9.8m/s. So it would have to be greater than that

8 0

3 years ago

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