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Brilliant_brown [7]
2 years ago
12

The rotor in a certain electric motor is a flat, rectangular coil with 80 turns of wire and dimensions 2.50 cm by 4.00 cm . The

rotor rotates in a uniform magnetic field of 0.800 T . When the plane of the rotor is perpendicular to the direction of the magnetic field, the rotor carries a current of 10.0 mA . In this orientation, the magnetic moment of the rotor is directed opposite the magnetic field. The rotor then turns through one-half revolution. This process is repeated to cause the rotor to turn steadily at an angular speed of 3.60×10³ rev/min. (d) What is the average power of the motor?
Physics
1 answer:
andreyandreev [35.5K]2 years ago
3 0

The average power of the motor is 0.153 Watt

To find the average power, the given values are,

No .of turns of the wire = 80

Dimensions is given as, 2.50 cm by 4.00 cm

Magnetic field = 0.800 T.

current = 10 mA.

Angular speed = 3.60 ×10³ rev/min

What is average power?

Average power is defined as the ratio of total work done by the body to the total time taken by the body.

Average power P avg = W / ΔT Watt

W - Work in One revolution

For first one half revolution,

W = 2 NIAB

   = 2× 80×10×10⁻³×0.0250×0.040×0.800× Sin 90°

   = 2 × 6.4 × 10 ⁻⁴

   = 1.2 × 10⁻³ J

For full revolution,

W = 2 × 1.2 × 10⁻³ J

   = 2.56 × 10⁻³ J

Calculating power,

Time for one revolution is  Δt = 60/3600 = 1/60s

Average power = W / Δt

                          = 2.56 x 10⁻³ / (1/60)

                          = 0.153 Watt.

The average power of the motor is 0.153 Watt.

Learn more about Average power,

brainly.com/question/27873045

#SPJ2

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Hahahahaha. Okay.

So basically , force is equal to mass into acceleration.

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fomenos

Complete Question

The complete question is shown on the uploaded image

Answer:

The nuclei experience a force that will move it to the right of the conductor rod while the electrons experience a force that will move it to the left side of the conductor rod.

Explanation:

The force that act on the charges(both the positive and the negative charge ) is Mathematically expressed as

                      F = qE   => E = F/q

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we can also see that the electric field is given as force per unit charge and generally the direction of this field is taken to be the direction of the force it would exert on a positive test charge

Now from the question we are being told that the external electric field is the direction of the positive x axis

Hence this field would drive the positive charge i.e the nuclei to the right.

In order to further explain let consider this

Generally the electric field is always radially outward  originating from a positive point charge and radially in toward a negative point charge.

what  this means for this question, is that the positive point charge is on the left side of the electric field while the negative point charge is at the right side of the field.

According to Coulomb's law which states that unlike term attract while like terms repel, it means that  the electron would move to the left of the conductor rod   while the nuclei would move to the right side of the conductor rod.

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Explanation:

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Sati [7]

Answer:

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Explanation:

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