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3 years ago

Which metal has the lowest atomic weight

Physics

2 answers:

Ray Of Light [21]3 years ago

7 0

Lithium, Li = 6.94 :)

Ber [7]3 years ago

7 0

Lithium, it is around 6.4 in atomic weight.

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Maria designs a test to see if lemon trees that receive more water produce larger lemons.

denis-greek [22]

Do you know the answer

7 0

3 years ago

The diagram below shows a boat moving north in a river at 3m/s while the current in the river moves south at 1 m/s.

salantis [7]

Answer it will move slower:

Explanation: cause the force that’s opposite of it

4 0

2 years ago

Using your best estimates, how many times would you have to slap a 1 kg rotisserie chicken in order to cook it? You can assume t

FromTheMoon [43]

Answer:

n= 16021.03 slaps

Explanation:

Using law of Energy conservation

E_{thermal}= Kinetic energy of hand

⇒ $mc\Delta T= n\frac{1}{2}m_hv_h^2$

m_h= mass of the hand = 0.4 kg

v_h= velocity of the hand = 10 m/s

n= number of slaps

c= 4180 J/Kg °C

m= mass of chicken = 1 kg

Assuming all the energy of hand goes into chicken

Given Ti=0°C and T_f= 170 F= 76.66°C

Now putting the values in above equation to get n

$1\times4180(76.66)= n\frac{1}{2}0.4\times10^2$

n= 16021.03 slaps

8 0

3 years ago

The watermelon is heaviest, followed by the soccer ball, golf ball and ping pong ball. How does the weight of an object relate t

Illusion [34]

Answer:

It doesn’t really relate

Explanation:

heavier load the parachute must be moving faster to match the downward force of the greater load

and approx terminal velocity when the parachute is open

velocity for Ping pong ball with parachute = 9m/s

velocity for Soccer ball with parachute = 15m/s

velocity for Golf ball with parachute =24m/s

velocity for Watermelon with parachute = 25m/s

so weight of an object doesn’t really realted how fast it falls with a parachute

6 0

4 years ago

An object weighs 79.1 N in air. When it is suspended from a force scale and completely immersed in water the scale reads 21.8 N.

Free_Kalibri [48]

Answer:

(a). The density of the object is 1382 kg/m³.

(b). The density of the oil is 536.4 kg/m³.

Explanation:

Given that,

Weight in air = 79.1 N

Weight in water = 21.8 N

Weight in oil = 48.4 N

We need to calculate the volume of object

Using formula of buoyant force

$F_{b}=W_{air}=W_{water}$

$F_{b}=79.1-21.8$

$F_{b}=57.3\ N$

$F_{b}=\rho g h$

Put the value into the formula

$57.3=1000\times V\times 9.8$

$V=\dfrac{57.3}{1000\times9.8}$

$V=5.84\times10^{-3}\ m^3$

We need to calculate the density

Using formula of buoyant force

$F_{b}=\rho Vg$

$79.1=\rho\times5.84\times10^{-3}\times9.8$

$\rho=\dfrac{79.1}{5.84\times10^{-3}\times9.8}$

$\rho=1382\ kg/m^3$

The density of the object is 1382 kg/m³.

(b). We need to calculate the volume of object

Using formula of buoyant force

$F_{b}=W_{air}=W_{oil}$

$F_{b}=79.1-48.4$

$F_{b}=30.7\ N$

We need to calculate the density

Using formula of buoyant force

$F_{b}=\rho_{oil} Vg$

$30.7=\rho_{oil}\times5.84\times10^{-3}\times9.8$

$\rho_{oil}=\dfrac{30.7}{5.84\times10^{-3}\times9.8}$

$\rho=536.4\ kg/m^3$

The density of the oil is 536.4 kg/m³.

Hence, This is the required solution.

4 0

3 years ago