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Nostrana [21]
3 years ago
7

Current I flows along the positive z-direction in the inner conductor of a long coaxial cable and returns through the outer cond

uctor. The inner conductor has radius a, and the inner and outer radii of the outer conductor are b and c, respectively. (a) Determine the magnetic field in each of the following regions: 0 ≤ r ≤ a, a ≤ r ≤ b, b ≤ r ≤ c, and r ≥ c. (b) Plot the magnitude of H as a function of r over the range from r = 0 to r = 10 cm, given that I = 10 A, a = 2 cm, b = 4 cm, and c = 5 c
Physics
1 answer:
PtichkaEL [24]3 years ago
5 0

Answer:

A) determine magnetic fields

For   0 ≤ r ≤ a

Magnetic field = ∅ \frac{rI}{2\pi a^2}

For  a ≤ r ≤ b

Magnetic field =  ∅ \frac{I}{2\pi r}

For   b ≤ r ≤ c

Magnetic field in the region = ∅ \frac{I}{2\pi r} [ c^2 - r^2 / c^2-b^2 ]

For  r ≥ c

magnetic filed in the region = 0

B ) attached below

Explanation:

<u>A) Determine the magnetic field in the following regions</u>

i) For   0 ≤ r ≤ a

Magnetic field = ∅ \frac{rI}{2\pi a^2}

attached below is the detailed solution

ii) For  a ≤ r ≤ b

Magnetic field =  ∅ \frac{I}{2\pi r}

attached below is the detailed solution

iii) For   b ≤ r ≤ c

Magnetic field in the region = ∅ \frac{I}{2\pi r} [ c^2 - r^2 / c^2-b^2 ]

attached below is the detailed solution

iv) For  r ≥ c

magnetic filed in the region = 0  and this is because the net current enclosed in the region = 0

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Under what conditions the reaction rate of an enzymolysis that follows Michaelis-Menten kinetics is a quarter of its maximum val
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Solution :

Michaelis-Menten kinetics in the field of biochemistry is considered as one of the well known models for enzyme kinetics. The model represents an equation that describes the enzymatic reactions's rate by relating the reaction rate to the substrate's concentration. The equation is named after the two famous scientists,  Leonor Michaelis and Maud Menten.

The formula is :

$v=\frac{V_{max}[S]}{K_M + [S]}$

where v = velocity of reaction

           $V_{max}$ = maximum rate achieved

           $K_M$ = Michaelis constant

           [S] = concentration of the substrate, S

According to the question, by putting the velocity of reaction, v as $\frac{V_{max}}{4}$, we get the above equation as

$[S]= \frac{K_M}{3}$

Therefore the answer is $[S]= \frac{K_M}{3}$

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3 years ago
Dry air is primarily composed of nitrogen. In a classroom demonstration, a physics instructor pours 3.6 L of liquid nitrogen int
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Answer:

The  value is  V_n  =  2.2498 \  m^3

Explanation:

From the question we are told that

   The volume of  liquid nitrogen is  V_n  =  3.6 \  L=  3.6 *10^{-3} \ m^3

   The  density of  nitrogen at gaseous form   is  \rho_n =  1.2929 \  kg/m^3  =  The dry air at sea level

   

Generally the density of nitrogen at liquid form is  

         \rho _l = 808 \  kg/m^3

And this is mathematically represented as

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=>   m  =  \rho_l  *  V_l

Now the density of  gaseous nitrogen is

       \rho_n  =  \frac{m}{V_n }

=>   m  =  \rho_n  *  V_n

Given that the mass is constant

       \rho_n  *  V_n  =   \rho_l  *  V_l

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=>   V_n  =  2.2498 \  m^3

       

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3 years ago
An 82 kg man, at rest, drops from a diving board 3.0 m above the surface of the water and comes to rest 0.55 s after reaching th
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Answer:

1626.4 N

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Using second equation of motion

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<h3><u>Answer;</u></h3>

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