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Karolina [17]
3 years ago
10

What angular velocity in revolution per second is needed for a centrifuge to produce an centripetal acceleration of a=9800m/s sq

uare at radius 10 cm.

Physics
1 answer:
max2010maxim [7]3 years ago
7 0

Option (d) is correct.

Explanation:

centripetal acceleration = a = r ω²

r= radius= 10 cm= 0.1 m

ω= angular velocity

9800= (0.1) ω²

ω=313 rad/sec

ω= 313 rad/s * (1 rev/2π rad)

ω=49.8 rev/s

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7 0
3 years ago
Which of the following would most likely be considered nonpoint source pollution
fredd [130]
The best answer is b) increased turbidity from erosion.

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8 0
4 years ago
The box is pushed to the right with a force of 40 Newtons and it just begins to move what is the maximum static frictional force
Vesnalui [34]

Answer:

The maximum static frictional force is 40N.

Explanation:

When an object of mass M is on a surface with a coefficient of static friction μ, there is a minimum force that you need to apply to the object in order to "break" the coefficient of static friction and be able to move the object (Called the threshold of motion, once the object is moving we have a coefficient of kinetic friction, which is smaller than the one for static friction).

This coefficient defines the maximum static friction force that we can have.

So if we apply a small force and we start to increase it, the static frictional force will be equal to our force until it reaches its maximum, and then we can move the object and now we will have frictional force.

In this case, we know that we apply a force of 40N and the object just starts to move.

Then we can assume that we are just at the point of transition between static frictional force and kinetic frictional force (the threshold of motion), thus, 40 N is the maximum of the static frictional force.

3 0
3 years ago
Un vagón de carga de 5000-kg se mueve a 2m/s e impacta a un vagón de 10000-kg que se encuentra en reposo. Después de la colisión
Mariulka [41]

Answer:

0.67 m/s

Explanation:

Mass of car 1, m₁ = 5000 kg

Mass of car 2, m₂ = 10,000 kg

Initial speed of car 1, u₁ = 2 m/s

Final speed of car 2, u₂ = 0 (at rest)

We need to find the final velocity of both cars when inelastic collision occurs. The momentum will remain conserved in case of inelastic collision. Using the conservation of momentum. Let V is the final speed.

m_1u_1+m_2u_2=(m_1+m_2)V\\\\\V=\dfrac{m_1u_1+m_2u_2}{(m_1+m_2)}\\\\V=\dfrac{m_1u_1}{(m_1+m_2)}\\\\V=\dfrac{5000\times 2}{(5000+10000)}\\\\V=0.67\ m/s

So, after the inelastic collision, they will move with a speed of 0.67 m/s.

6 0
3 years ago
How do you find the weight of an object underwater
iren2701 [21]

Answer:

Explanation:

But Archimedes principle states that the buoyant force = weight of fluid displaced by object. From this volume you can get the mass of water displaced since the density of water is 977kg/m^3. Whatever you get multiply it by 9.8m/s^2 to covert mass to weight.

4 0
4 years ago
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