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Liono4ka [1.6K]
3 years ago
12

The box is pushed to the right with a force of 40 Newtons and it just begins to move what is the maximum static frictional force

Physics
1 answer:
Vesnalui [34]3 years ago
3 0

Answer:

The maximum static frictional force is 40N.

Explanation:

When an object of mass M is on a surface with a coefficient of static friction μ, there is a minimum force that you need to apply to the object in order to "break" the coefficient of static friction and be able to move the object (Called the threshold of motion, once the object is moving we have a coefficient of kinetic friction, which is smaller than the one for static friction).

This coefficient defines the maximum static friction force that we can have.

So if we apply a small force and we start to increase it, the static frictional force will be equal to our force until it reaches its maximum, and then we can move the object and now we will have frictional force.

In this case, we know that we apply a force of 40N and the object just starts to move.

Then we can assume that we are just at the point of transition between static frictional force and kinetic frictional force (the threshold of motion), thus, 40 N is the maximum of the static frictional force.

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Answer:

a. False

Explanation:

For an object to be moving at a constant velocity, a net force of 0 N would be required.

Newton's 1st Law of Motion states that an object will remain at rest unless acted upon by an unbalanced force, and an object will remain in motion unless acted upon by an unbalanced force.

Therefore, the unbalanced force of 6 N would not allow the rock to maintain its constant speed.

The answer to this question is A) False.

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3 years ago
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Answer:

C. 640

Explanation:

The minimum force would occur in a frictionless environment and act parallel to any abutting surface.

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2 years ago
How far (in feet) could a pitcher throw a baseball on flat, level ground if he can throw it at 100mph? (Neglect wind drag and th
ehidna [41]

Answer:

R = 668.19 ft  

Explanation:

given,

speed of the ball thrown by the pitcher = 100 mph

to travel maximum distance θ = 45°

distance traveled by the ball = ?

using formula

1 mph = 0.44704 m/s

100 mph = 44.704 m/s

R = \dfrac{u^2sin2\theta}{g}

R = \dfrac{44.704^2sin2\times 45}{9.81}

R = 203.71 m

1 m  = 3.28 ft

R = 203.71 × 3.28

R = 668.19 ft  

hence, ball will go at a distance of 668.19 ft   when pitcher throw it at 100 mph.

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saveliy_v [14]

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Explanation:

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