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katen-ka-za [31]
3 years ago
6

Which of the following are true of phases?Check all that apply.A.The particles in a liquid are in a fixed location.B.Gases have

more kinetic energy than liquids or solids.C.The particles of a solid vibrate.D.Gases have weak intermolecular forces between the atoms or molecules.
Chemistry
1 answer:
Snezhnost [94]3 years ago
7 0

Answer:

c

solids do vibrate very minutely\

Explanation:

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When a hot piece of iron is placed in cool water,
Papessa [141]
A i believe is the answer
8 0
3 years ago
20 POINTS!!!!......
tester [92]
Density= mass/ volume

So density = 99/10= 9.9g/cm^3

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5 0
3 years ago
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How many excess electrons must be added to an isolated spherical conductor 41.0 cmcm in diameter to produce an electric field of
alina1380 [7]

Answer:

3.65 x 10¹⁰ electrons

Explanation:

we'll apply the following equation for electric field of a point charge on a spherical conductor

E = k \frac{q}{r^{2} }

where E is the electric field

k is a constant of the value 8.99 x 10⁹ Nm²/C²

r is the radius of the spherical conductor

q is the total charge in the sphere

Given diameter d =41.0cm, radius r = 20.5cm = 0.205m (convert cm to m)

Electrical field E = 1250 N/C

we are asked to determine how many excess electrons must be added to the surface of the sphere to produce this electric field

E = k \frac{q}{r^{2} }

q = <u>E x r²</u>

        k

q =  <u>1250 N/C x 0.205m</u>²

       8.99 x 10⁹ Nm²/C²

q =   5.84 x 10⁻⁹ C

this is the total charge in the sphere

To determine the number of electrons, we can divide the charge q by the charge on an electron e (1.6 x 10⁻¹⁹C)

n = \frac{q}{e}

n = <u>5.84 x 10⁻⁹ C </u>

       1.6 x 10⁻¹⁹C

n = 3.65 x 10¹⁰ electrons

Therefore, to apply an electric field of magnitude 1250 N/C, the isolated spherical conductor must contain 3.65 x 10¹⁰ electrons

3 0
3 years ago
The major reaction of the unsaturated compounds is:
antiseptic1488 [7]
Its B addition

where an atom adds to the broken double bond of a hydrocarbon and saturates it 

hope that helps
3 0
3 years ago
Read 2 more answers
A sample of oxygen occupied 626 mL when the pressure increased to 874.27 mm Hg. At constant temperature, what volume did the gas
Usimov [2.4K]

Answer:

709 (With sig figs)

Explanation:

Pressure(1) * volume(1) = Pressure(2) * volume(2)

771.75 mm Hg * unknown = 874.27 mm Hg * 626 mL

771.75 mm Hg * unknown = 547,293.02 mm Hg*mL

   Divide both sides by 771.75 mm Hg

Unknown = 709 (With sig figs)....709.158432 (without sig figs)

4 0
2 years ago
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