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Yakvenalex [24]
3 years ago
7

A group of birds eat fruit from a tree. The fruit falls to the ground where

Chemistry
1 answer:
olchik [2.2K]3 years ago
3 0

Answer:

Both answer choice 2 and answer choice 3 are correct choices.

Explanation:

Biotic factors are living components in an ecosystem. They are living organisms which affect another living component in an ecosystem.

Antibiotic factors are non living components of an ecosystem. They are chemicals which affect living organisms.

The choice 2 is correct. The seeds spread out by mice is a biotic factor interacting with an antibiotic factor

Choice 3 is correct. The seeds in the soil grow into new trees are biotic factors interacting with an antibiotic factor

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The activation energy of a certain uncatalyzed reaction is 64 kJ/mol. In the presence of a catalyst, the Ea is 55 kJ/mol. How ma
Ksivusya [100]

Answer:

About 5 times faster.

Explanation:

Hello,

In this case, since the Arrhenius equation is considered for both the catalyzed reaction (1) and the uncatalized reaction (2), one determines the relationship between them as follows:

\frac{k_1}{k_2}=\frac{Aexp(-\frac{Ea_1}{RT} )}{Aexp(-\frac{Ea_2}{RT})}  \\\frac{k_1}{k_2}=\frac{exp(-\frac{Ea_1}{RT} )}{exp(-\frac{Ea_2}{RT})}

By replacing the corresponding values we obtain:

\frac{k_1}{k_2}=\frac{exp(-\frac{55000J/mol}{8.314J/molK*673.15K} )}{exp(-\frac{64000J/mol}{8.314J/molK*673.15K} )} =4.8

Such result means that the catalyzed reaction is about five times faster than the uncatalyzed reaction.

Best regards.

4 0
3 years ago
The burning of coal, a fossil fuel, produces water and carbon dioxide. How is this similar to cellular respiration?
Mrac [35]

Answer:

I think the answer is C but you might need a second opinion on this answer

6 0
3 years ago
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An experimental spacecraft consumes a special fuel at a rate of 372 L/min. The density of the fuel is 0.730 g/mL and the standar
Karolina [17]

Explanation:

First, we will calculate fuel consumption is as follows.

         372 L/min \times 1000 ml/L \times 0.730 g/ml \times \frac{1}{60} min/s

           = 4526 g/s

Now, we will calculate the power as follows.

        Power = Fuel consumption rate × -enthalpy of combustion

                    = 4526 g/s \times -26.5 kJ/g

                    = 1.19 \times 10^{5} kW

Thus, we can conclude that maximum power (in units of kilowatts) that can be produced by this spacecraft is 1.19 \times 10^{5} kW.

5 0
3 years ago
How does the cardiovascular system help the body get rid of waste??
Pani-rosa [81]
The answer is the rectum 
4 0
3 years ago
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Find the pH of a solution whose H concentration is 0.7 x 10-3.
dexar [7]

Answer: pH = 3.15

Explanation: Solved in the attached picture.

6 0
2 years ago
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