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zavuch27 [327]
3 years ago
12

Determine the number of ions produced in the dissociation of the compound listed. AlF3

Chemistry
1 answer:
scoray [572]3 years ago
6 0
Answer is: the number of ions produced in the dissociation of aluminium fluoride is 4.
<span>
Chemical dissociation of aluminium fluoride in water:
AlF</span>₃(aq) → Al³⁺(aq) + 3F⁻(aq).<span>
There are four ions, one aluminium cation and three fluoride anions.
Aluminium has oxidation +3, because it lost three electrons, to have electron configuration as noble gas neon and fluorine has oxidation -1, because it gain one electron to </span>have electron configuration as noble gas neon.
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An object has a mass of 3.50 grams and a density of 5.61 g/mL. What is the volume of this object? *
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Answer:

<h2>0.62 mL</h2>

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

volume =  \frac{mass}{density} \\

From the question we have

volume =  \frac{3.50}{5.61}  \\  = 0.6238859...

We have the final answer as

<h3>0.62 mL</h3>

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