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2 years ago

Write the uses of Ions .

Chemistry

1 answer:

Montano1993 [528]2 years ago

4 0

Answer:

This is what they are: An ion is a charged atom or molecule. It is charged because the number of electrons do not equal the number of protons in the atom or molecule. An atom can acquire a positive charge or a negative charge depending on whether the number of electrons in an atom is greater or less then the number of protons in the atom.

This is their purpose: Once they reach our bloodstream, negative ions are believed to produce biochemical reactions that increase levels of the mood chemical serotonin, helping to alleviate depression, relieve stress, and boost our daytime energy.

Explanation:

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Microwave ovens heat food by creating microwave electromagnetic radiation that is absorbed by water molecules in the food.

Nikolay [14]

Explanation:

It is known that relation between heat energy and temperature change is as follows.

Q = $mC \Delta T$

where, q = heat energy

m = mass of the solution or solvent

$\Delta T$ = change in temperature

Hence, putting the given values into the above formula as follows.

Q = $mC \Delta T$

= $110.0 g \times \frac{315 J}{75^{o}C} \times (100 - 25)^{o}C$

= 34650 J

Now, calculate the energy of photons at wavelength 3.02 mm as follows.

E = $\frac{hc}{\lambda}$

where, h = planks constant = $6.626 \times 10^{-34} Js$

c = velocity of light = $3 \times 10^{8}$ m/s

$\lambda$ = wavelength = 3.02 mm = $3.02 \times 10^{-3}$ m (as 1 m = 1000 mm)

Therefore, putting the given values into the above formula as follows.

E = $\frac{hc}{\lambda}$

= $\frac{6.626 \times 10^{-34} Js \times 3 \times 10^{8} m/s}{3.02 \times 10^{-3} m}$

= $6.58 \times 10^{-23}$ J

Now, the number of photons required of energy $6.58 \times 10^{-23}$ J/photon for the total energy of 34650 J as follows.

$E_{total} = n \times E$

n = $\frac{E_{total}}{E}$

= $\frac{34650 J}{6.58 \times 10^{-23}}$

= $5265.95 \times 10^{23}$ photons

or, = $5.265 \times 10^{26}$ photons

Thus, we can conclude that the minimum number of photons present are $5.265 \times 10^{26}$ .

7 0

3 years ago

A 2.06g sample of agno3•xh2o is dissolved in an aqueous solution of excess nacl. The resulting agcl precipitate is filtered off

irakobra [83]

Answer:

Explanation:

NaCl + AgNO₃ ———> NaNO₃ + AgCl.

Firstly, we will need to calculate the number of moles of AgCl produced. That is equal to the mass produced divided by the molar mass of AgCl.

The molar mass of AgCl = 108 + 35.5 = 143.5g/mol

The number of moles is thus 1.32/143.5 = 0.0092 moles

Since silver nitrate and silver chloride contains one atom of silver, it is only possible that their mole ratios are equal. Hence we say that 0.0092 moles of silver nitrate hydrate was dissolved.

Now we go on to calculate the molar mass of the silver nitrate hydrate.

The molar mass is simply the mass divided by the number of moles.

That is 2.06/0.0092 = 223.9 = 224g/mol

We can now calculate the value of x from here.

AgNO3.xH2O

(108 + 14 + 48) + x(2+ 16) = 224

170 + 18x = 224

18x = 224 - 170 = 54

18x = 54

x = 54/18 = 3

8 0

3 years ago

How do i find the molar mass of NaOh and Cr(C2H3O2)? i'm a little stuck =/?

Pachacha [2.7K]

$M_{NaOH}=23\frac{g}{mol}+16\frac{g}{mol}+1\frac{g}{mol}=40\frac{g}{mol}\\\\
M_{Cr(C_{2}H_{3}O_{2})3}=52\frac{g}{mol}+3*(2*12\frac{g}{mol}+3*1\frac{g}{mol}+2*16\frac{g}{mol})=\\\\=229\frac{g}{mol}$