Answer:
0.45 M
Explanation:
Now we need to make use of the dilution formula
C1V1= C2V2
C1= initial molarity of the solution which is the unknown
V1 = initial volume of the solution which is 175 ml
C2 =final molarity of the solution= 0.315 M
V2= final volume of solution= 250 ml
From C1V1= C2V2 we have;
C1= C2V2/V1
C1= 0.315 × 250/ 175
C1= 0.45 M
<u>Answer:</u> The enthalpy of the reaction is coming out to be -902 kJ.
<u>Explanation:</u>
Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. It is represented as 
The equation used to calculate enthalpy change is of a reaction is:
![\Delta H_{rxn}=\sum [n\times \Delta H_f_{(product)}]-\sum [n\times \Delta H_f_{(reactant)}]](https://tex.z-dn.net/?f=%5CDelta%20H_%7Brxn%7D%3D%5Csum%20%5Bn%5Ctimes%20%5CDelta%20H_f_%7B%28product%29%7D%5D-%5Csum%20%5Bn%5Ctimes%20%5CDelta%20H_f_%7B%28reactant%29%7D%5D)
For the given chemical reaction:
The equation for the enthalpy change of the above reaction is:
![\Delta H_{rxn}=[(4\times \Delta H_f_{(NO(g))})+(6\times \Delta H_f_{(H_2O(g))})]-[(4\times \Delta H_f_{(NH_3(g))})+(5\times \Delta H_f_{(O_2)})]](https://tex.z-dn.net/?f=%5CDelta%20H_%7Brxn%7D%3D%5B%284%5Ctimes%20%5CDelta%20H_f_%7B%28NO%28g%29%29%7D%29%2B%286%5Ctimes%20%5CDelta%20H_f_%7B%28H_2O%28g%29%29%7D%29%5D-%5B%284%5Ctimes%20%5CDelta%20H_f_%7B%28NH_3%28g%29%29%7D%29%2B%285%5Ctimes%20%5CDelta%20H_f_%7B%28O_2%29%7D%29%5D)
We are given:
Putting values in above equation, we get:
![\Delta H_{rxn}=[(4\times (91.3))+(6\times (-241.8))]-[(4\times (-45.9))+(5\times (0))]\\\\\Delta H_{rxn}=-902kJ](https://tex.z-dn.net/?f=%5CDelta%20H_%7Brxn%7D%3D%5B%284%5Ctimes%20%2891.3%29%29%2B%286%5Ctimes%20%28-241.8%29%29%5D-%5B%284%5Ctimes%20%28-45.9%29%29%2B%285%5Ctimes%20%280%29%29%5D%5C%5C%5C%5C%5CDelta%20H_%7Brxn%7D%3D-902kJ)
Hence, the enthalpy of the reaction is coming out to be -902 kJ.
Answer:
the reaction is: Na2CO3 + 2HCl ===》 2NaCl + H2O + CO2(g)
Consider the formation of water molecule. Hydrogen combines with oxygen to form a water molecule.
In this case, the total mass of the reactants = total mass of the products. Also, the number of atoms of hydrogen and oxygen in the reactants side and the products side are equal.
that's all I know
Molecular orbital energy is the energy associated with each electron in an atom or molecule.
It is expressed in electron volts (eV) and is determined by the electron's position in the atom or molecule. The molecular orbital energy diagram and fill-in the electrons are given here in each case, the number of valence electrons in the species is determined first; this is followed by the valence molecular orbital diagram for each species.
C2+: Molecular Orbital Energy Diagram
1s2 2s2 2p2
σ2s* ← 0 e-
σ2s ← 2 e-
σ2p* ← 0 e-
σ2p ← 0 e-
π2p* ← 0 e-
π2p ← 0 e-
Bond Order: 0
Stability: Unstable
Magnetism: Diamagnetic (no unpaired electrons)
O2-: Molecular Orbital Energy Diagram
1s2 2s2 2p4
σ2s* ← 0 e-
σ2s ← 2 e-
σ2p* ← 0 e-
σ2p ← 2 e-
π2p* ← 0 e-
π2p ← 2 e-
Bond Order: 1
Stability: Stable
Magnetism: Paramagnetic (2 unpaired electrons)
For more questions like Molecular orbital theory click the link below:
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