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HACTEHA [7]
3 years ago
14

17. The number of waves that pass a particular point in a body in a unit of time is called the _______ of the waves. A. rarefact

ion B. amplitude C. frequency D. compression
Physics
1 answer:
EastWind [94]3 years ago
3 0
<span>The number of waves that pass a particular point in a body in a unit of time is called the frequency of the waves. The unit of requency is Hz (hertz). The frequency counts how many cycles were made per second</span>
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Two power lines run parallel for a distance of 222 m and are separated by a distance of 40.0 cm. if the current in each of the t
earnstyle [38]
1) Magnitude of the force:

The magnetic field generated by a current-carrying wire is
B= \frac{\mu_0I}{2 \pi r}
where
\mu_0 is the vacuum permeability
I is the current in the wire
r is the distance at which the field is calculated

Using I=135 A, the current flowing in each wire, we can calculate the magnetic field generated by each wire at distance 
r=40.0 cm=0.40 m, 
which is the distance at which the other wire is located:
B= \frac{\mu_0 I}{2 \pi r}= \frac{(4 \pi \cdot 10^{-7} N/A^2)(135 A) }{2 \pi (0.40 m)}=6.75 \cdot 10^{-5} T

Then we can calculate the magnitude of the force exerted on each wire by this magnetic field, which is given by:
F=ILB=(135 A)(222 m)(6.75 \cdot 10^{-5}T)=2.03 N

2) direction of the force: 
The two currents run in opposite direction: this means that the force between them is repulsive. This can be determined by using the right hand rule. Let's apply it to one of the two wires, assuming they are in the horizontal plane, and assuming that the current in the wire on the right is directed northwards:
- the magnetic field produced by the wire on the left at the location of the wire on the right is directed upward (the thumb of the right hand is directed as the current, due south, and the other fingers give the direction of the magnetic field, upward)

Now let's apply the right-hand rule to the wire on the right:
- index finger: current --> northward
- middle finger: magnetic field --> upward
- thumb: force --> due east --> so the force is repulsive

A similar procedure can be used on the wire on the left, finding that the force exerted on it is directed westwards, so the force between the two wires is repulsive.
6 0
2 years ago
Indiana jones (83.5 kg) is running 3.75 m/s when he jumps in a stationary 312 kg mine cart. what is their joint velocity afterwa
Lubov Fominskaja [6]

Answer:

.7917 m/s

Explanation:

This is a conservation of momentum question. You have an object initially at rest (cart) so that object is initially at 0 momentum. Indiana Jones is 83.5 kg and running 3.75 m/s so he starts with a momentum of 313.125 kg * m/s because momentum is equal to mass * velocity. Once the person jumps in the cart, the cart and the person can be considered one object and by conservation of momentum, the momentum of the Indiana-cart system is equal to 313.125 kg * m/s. By that, we can set that momentum equal to the combined mass * joint velocity. So 313.125 = (83.5kg + 312kg) * joint velocity. Then just solve for the velocity. The answer should be smaller than the intial velocity of the person of 3.75 m/s because the mine cart is HUGE at 312kg.

3 0
3 years ago
Which object has the most gravitational potential energy?
Kipish [7]

Answer: An 8 kg book at a height of 3 m has the most gravitational potential energy.

Explanation:

Gravitational potential energy is the product of mass of object, height of object and gravitational field.

So, formula to calculate gravitational potential energy is as follows.

U = mgh

where,

m = mass of object

g = gravitational field = 9.81 m/s^{2}

h = height of object

(A) m = 5 kg and h = 2m

Therefore, its gravitational potential energy is calculated as follows.

U = mgh\\= 5 kg \times 9.81 m/s^{2} \times 2 m\\= 98.1 J    (1 J = kg m^{2}/s^{2})

(B) m = 8 kg and h = 2 m

Therefore, its gravitational potential energy is calculated as follows.

U = mgh\\= 8 kg \times 9.81 m/s^{2} \times 2 m\\= 156.96 J    (1 J = kg m^{2}/s^{2})

(C) m = 8 kg and h = 3 m

Therefore, its gravitational potential energy is calculated as follows.

U = mgh\\= 8 kg \times 9.81 m/s^{2} \times 3 m\\= 235.44 J    (1 J = kg m^{2}/s^{2})

(D) m = 5 kg and h = 3 m

Therefore, its gravitational potential energy is calculated as follows.

U = mgh\\= 5 kg \times 9.81 m/s^{2} \times 3 m\\= 147.15 J    (1 J = kg m^{2}/s^{2})

Thus, we can conclude that an 8 kg book at a height of 3 m has the most gravitational potential energy.

3 0
3 years ago
A small metal bead, labeled A, has a charge of 28 nC .It is touched to metal bead B, initially neutral, so that the two beads sh
Dmitry_Shevchenko [17]

Answer:

Explanation:

Let the charge on bead A be q nC  and the charge on bead B be 28nC - qnC

Force F between them

4.8\times10^{-4} = \frac{9\times10^9\times q\times(28-q)\times10^{-18}}{(5\times10^{-2})^2}

=120 x 10⁻⁸ = 9 x q(28 - q ) x 10⁻⁹

133.33 = 28q - q²

q²- 28q +133.33 = 0

It is a quadratic equation , which has two solution

q_A = 21.91 x 10⁻⁹C or q_B = 6.09 x 10⁻⁹ C

3 0
3 years ago
A package is dropped from a helicopter moving upward at 15m/s. If it takes 10 s before the package strikes the ground, how high
Vlad1618 [11]

Answer:

A package is dropped from a helicopter moving upward at 15 m/s. If it takes 16.0 s before the package strikes the ground, how high above the ground was the package when it was released? (Disregard air resistance.)

Show step by step please.

Note: The answer is given it's should be 1000 m ??

This what i can up with so see what it is kid

Explanation:

6 0
3 years ago
Read 2 more answers
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