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9966 [12]
3 years ago
14

a rocket of mass 100,000 kg undergoes an acceleration of 2m/s2. show the net force acting on it is 200,000

Physics
1 answer:
just olya [345]3 years ago
6 0
M= 100000 kg
a= 2m/s²

Use Newton's second law:
F=ma=100000kg • 2 m/s²
= 200000 N
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Displacement is the difference between the initial position and the____ position of an object
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The magnitude of the electrical force acting between a +2.4 x 10- C charge and a +1.8 x 10- C charge that are separated
Brrunno [24]

Answer: 6.07 N

Explanation:

According to Coulomb's Law:  

F_{E}= K\frac{q_{1}.q_{2}}{d^{2}}  

Where:

F_{E}  is the electrostatic force

K=8.99(10)^{9} Nm^{2}/C^{2} is the Coulomb's constant  

q_{1}=2.4(10)^{-8} C and q_{2}=1.8(10)^{-6} C are the electric charges

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Solving:

F_{E}= 8.99(10)^{9} Nm^{2}/C^{2}\frac{(2.4(10)^{-8} C)(1.8(10)^{-6} C)}{(0.008 m)^{2}}  

F_{E}=6.07 N  

3 0
4 years ago
Which graph best represents the relationship between the conductivity and the temperature of semiconductors ?​
Volgvan

Answer: I think the answer is B

Explanation:

6 0
3 years ago
Read 2 more answers
1. A heat lamp is designed to keep food and other things warm. Would it also make a good tanning lamp? Why or why not?
NemiM [27]
1. becuase it is so hot that it could tan or be used to keep warm.
4 0
3 years ago
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A 1.2 kg block of wood hangs motionless from strings. A 50 gram bullet, traveling horzontally, strikes the block and becomes emb
Firdavs [7]

Answer:

speed of the bullet before it hit the block is 200 m/s

Explanation:

given data

mass of block m1 = 1.2 kg

mass of bullet m2 = 50 gram = 0.05 kg

combine speed V= 8.0 m/s

to find out

speed of the bullet before it hit the block

solution

we will apply here conservation of momentum that is

m1 × v1 + m2 × v2 = M × V    .............1

here m1 is mass of block and m2 is mass of bullet and v1 is initial speed of block i.e 0 and v2 is initial speed of bullet and M is combine mass of block and bullet and V is combine speed of block and bullet

put all value in equation 1

m1 × v1 + m2 × v2 = M × V

1.2 × 0 + 0.05 × v2 = ( 1.2 + 0.05 ) × 8

solve it we get

v2 = 200 m/s

so speed of the bullet before it hit the block is 200 m/s

8 0
3 years ago
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