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yan [13]
3 years ago
12

What mass of K2SO4 would you measure out to prepare 550 ml of a 0.76 M solution

Chemistry
2 answers:
Nikolay [14]3 years ago
5 0
The molecular weight of K2SO4 is 174.26 g/mole. The mass of K2SO4 required to make this solution is calculated in the following way. 
550mL * (0.76mole/1000mL) * (174.26g/mole) = 72.84gram
<span>I hope this helps.</span>
yulyashka [42]3 years ago
5 0

Answer:

m_{K_2SO_4}=72.84gK_2SO_4

Explanation:

Hello,

In this case, by considering that the both the volume of the solution of potassium sulfate and its concentration are given, one solves for the required mass considering the following proportional factors related stoichiometrically:

m_{K_2SO_4}=550mLsln*\frac{1Lsln}{1000mLsln}*0.76\frac{molK_2SO_4}{Lsln}*\frac{174.259gK_2SO_4}{1molK_2SO_4}\\  m_{K_2SO_4}=72.84gK_2SO_4

Best regards.

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What is the correct formula for combining Mg2+ and Br1+
True [87]

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Explanation:

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Answer:

Value of Q_{p} for the given redox reaction is 1.0\times 10^{-8}

Explanation:

Redox reaction with states of species:

14H^{+}(aq.)+Cr_{2}O_{7}^{2-}(aq.)+6Cl^{-}(aq.)\rightarrow 2Cr^{3+}(aq.)+3Cl_{2}(g)+7H_{2}O(l)

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