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3 years ago

What mass of K2SO4 would you measure out to prepare 550 ml of a 0.76 M solution

2 answers:

5 0

The molecular weight of K2SO4 is 174.26 g/mole. The mass of K2SO4 required to make this solution is calculated in the following way.
550mL * (0.76mole/1000mL) * (174.26g/mole) = 72.84gram
I hope this helps.

yulyashka [42]3 years ago

5 0

Answer:

$m_{K_2SO_4}=72.84gK_2SO_4$

Explanation:

Hello,

In this case, by considering that the both the volume of the solution of potassium sulfate and its concentration are given, one solves for the required mass considering the following proportional factors related stoichiometrically:

$m_{K_2SO_4}=550mLsln*\frac{1Lsln}{1000mLsln}*0.76\frac{molK_2SO_4}{Lsln}*\frac{174.259gK_2SO_4}{1molK_2SO_4}\\ m_{K_2SO_4}=72.84gK_2SO_4$

Best regards.

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abruzzese [7]

Answer:

I guess D ...,...,.....

3 0

3 years ago

6) A 14.5 g sample of sodium chloride reacts with excess fluorine gas according to

Ann [662]

The mass of chlorine gas produced by 14.5 grams of sodium chloride is 10.42 g.

The mass of chlorine gas produced by 14.5 grams of sodium chloride is 8.81 g.

The given parameters;

mass of the sodium chloride, = 14.5 g
2NaCl(s) + F2(g) → 2NaF(s) + Cl2(g)

In the reaction above, we can deduce the following;

molecular mass of 2Nacl = 2(58.44) = 116.88 g

molecular mass of 2NaF = 2(42) = 84 g

molecular mass of Cl2 = 71 g

The mass of sodium fluoride produced by 14.5 grams of sodium chloride is calculated as follows;

116.88 g of NaCl --------------- 84 g of NaF

14.5 g of NaCl ------------------- ?

$= \frac{84 \times 14.5}{116.88} \\\\= 10.42 \ g$

The mass of chlorine gas produced by 14.5 grams of sodium chloride is calculated as follows;

116.88 g of NaCl --------------- 71 g of Cl2

14.5 g of NaCl ------------------- ?

$= \frac{14.5 \times 71}{116.88} \\\\= 8.81 \ g$

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8 0

3 years ago

If five moles of a gas at a pressure of 5.4 kpa have a volume of 120 liters, what is the temperature?

ra1l [238]

<h3>The temperature is 15.58 kelvin </h3>

Solution:

Ideal gas equation is given as:

$PV = nRt$

Where,

P = pressure

V = volume

n = amount of substance

R = ideal gas constant

T = temperature

From given,

V = 120 liters

n = 5 moles

$R = 8.314\ \frac{Lkpa}{mol\ K}$

P = 5.4 kPa

T = ?

Therefore,

$5.4 \times 120 = 5 \times 8.314 \times T\\\\648 = 41.57 \times T\\\\T = 15.58\ kelvin$

Thus the temperature is 15.58 kelvin

4 0

3 years ago

One mole of a metallic oxide reacts with one mole of hydrogen to produce two moles of the pure metal

MAXImum [283]

Answer:

The metallic oxide is Li₂O

Explanation:

Let the metallic oxide be M₂O

Thus;

M₂O + H₂ = 2M + H₂O

Molar mass of M₂O = (2x + 16)

We assume Molar mass of M to be x.

We are told that 5.00 g of the metallic oxide produces 2.32 g of the metal.

By proportion, we can write the following;

5g of M₂O × (1 mole of M₂O/(2x + 16)) × (2 moles of M/1 mole of M₂O) = 2.32 g of M × 1 mole of M/x g of M

This cancels out to give us;

10/(2x + 16) = 2.32/x

Cross multiply to get;

10x = 2.32(2x + 16)

10x = 4.64x + 37.12

10x - 4.64x = 37.12

5.36x = 37.12

x = 37.12/5.36

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The metal with a molar mass closest to this value of x is Lithium which has a molar mass of 6.94 g/mol

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3 years ago

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3 years ago